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Vikki [24]
3 years ago
9

Using atomic weight crystal structure and atomic radius data tabulated inside the front cover compute the theoritical densities

of alminuim ,nikel......
Physics
1 answer:
stellarik [79]3 years ago
8 0

Question

Using atomic weight, crystal structure, and atomic radius data tabulated inside the front cover of thebook, compute the theoretical densities of aluminum (Al), nickel (Ni), magnesium (Mg), and tungsten (W), and thencompare these values with the measured densities listed in this same table. The c/a ratio for magnesium is 1.624.

Explanation:

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Families or ____ of elements are similar in their number of valence electrons
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Answer:

groups

Explanation:

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The net force of the diagram below is
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the correct answer is a

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4 years ago
A metal rod with a length of 22.0cm lies in the xy-plane and makes an angle of 37.9 degrees with the positive x-axis and an angl
Shtirlitz [24]

Answer:

Induced emf in the rod is, \epsilon=0.08262\ V

Explanation:

Given that,

Length of the rod, L = 22 cm = 0.22 m

Angle with x axis is 37.9 degrees with the positive x-axis and an angle of 52.1 degrees with the positive y-axis.

L=0.22(cos37.9\ i)+0.22(sin37.9\ j)

L=(0.173\ i+0.135\ j)\ m

Velocity of the rod, v = 6.8i m/s

Magnetic field, B=0.170i-0.24j-0.09k

The formula for the emf induced in the rod is given by :

\epsilon=(v\times B){\cdot}L

\epsilon=(6.8i\times (0.170i-0.24j-0.09k)){\cdot} (0.173\ i+0.135\ j)      

\epsilon=(0.612j-1.632k){\cdot}(0.173i+0.135j)      

\epsilon=0.08262\ V

So, the magnitude of the emf induced in the rod is 0.08262 volts. Hence, this is the required solution.                                      

8 0
3 years ago
The mirror used in search light is:
dolphi86 [110]

Answer:

B

Explanation:

6 0
3 years ago
A physicist performing a sensitive measurement wants to limit the magnetic force on a moving charge in her equipment to less tha
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Answer:

Maximum charge will be 6.66\times 10^{-9}C

Explanation:

We have given force ion the moving charge F=10^{-12}N

Maximum speed of the moving charge v = 30 m /sec

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Force on moving charge is given by

F=qvB

So 10^{-12}=q\times 30\times 5\times 10^{-5}

q=6.66\times 10^{-9}C

Maximum charge will be 6.66\times 10^{-9}C

5 0
4 years ago
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