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alekssr [168]
3 years ago
9

The mirror used in search light is:

Physics
1 answer:
dolphi86 [110]3 years ago
6 0

Answer:

B

Explanation:

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Which person is weightless?
ahrayia [7]

Answer: Option (b) is the correct answer.

Explanation:

The force of gravity acting on an object helps in determining the weight of an object. But a place where there will be no gravity or have zero gravitational pull then it means the person will be weightless.

For example, force of gravity on moon is zero which means any object or person on moon will be weightless.

On the other hand, when a child is in the air as she plays on a trampoline then it means gravitational pull form the earth is acting on it. So, it will definitely has some weight.

Similarly, a scuba diver exploring a deep-sea wreck is under the ground where there will be force of gravity. Hence, it will also have some weight.

Thus, we can conclude that an astronaut on the Moon is the person who is weightless.

7 0
3 years ago
Somebody please help I need exuse to not go to pe because I injured my self anybody know what to say
algol13

Answer:

Say you feel like you twisted ur ankle or can move your foot or something in that category

3 0
3 years ago
Can I PLEASE get some help?
Rus_ich [418]
1.) C
2.) B
3.) D
4.) B
Good luck with your work!
3 0
4 years ago
an object at rest has no ________ energy, but it may have ________ energy resulting from its location or structure.
77julia77 [94]

Answer: first blank: kinetic

Second blank: potential

Explanation:

Hope this helps and please consider choosing me for Brainiest!

5 0
3 years ago
A small bolt with a mass of 41.0 g sits on top of a piston. The piston is undergoing simple harmonic motion in the vertical dire
EleoNora [17]

Answer:

Amplitude will be equal to 0.091 m

Explanation:

Given mass of the slits = 41 gram = 0.041 kg

Frequency f = 1.65 Hz

So angular frequency \omega =2\pi f=2\times 3.14\times 1.65=10.362rad/sec

Angular frequency is equal to \omega =\sqrt{\frac{k}{m}}

10.362 =\sqrt{\frac{k}{0.041}}

Squaring both side

107.371 ={\frac{k}{0.041}}

k = 4.40 N/m

For vertical osculation

mg=kA

0.041\times 9.8=4.40\times A

A = 0.091 m

So amplitude will be equal to 0.0391 m

8 0
3 years ago
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