Answer:
a. 0.8 cm
Explanation:
The distance of the object from the lens, u = 1 cm
The magnification of the lens, m = 5
The focus of a lens formula is given as follows;
The magnification of the lens, m = -v/u
Where;
v = The distance of the image from the lens
Therefore, we have;
v = m × u
∴ v = 5 × 1 cm = 5 cm (on the other side of the lens)
From which we get;
The focal length ≈ 0.8 cm
Answer:
a) The change in potential energy of a 3.0 kilograms backpack carried up the stairs.
b) The change in potential energy of a persona with weight 650 newtons that descends the stairs is -2665 joules.
Explanation:
Let consider the bottom of the first floor in a building as the zero reference (). The change in potential energy experimented by a particle (
), measured in joules, is:
(1)
Where:
- Mass, measured in kilograms.
- Gravitational acceleration, measured in meters per square second.
,
- Initial and final height with respect to zero reference, measured in meters.
Please notice that is the weight of the particle, measured in newtons.
a) If we know that ,
,
and
, then the change in potential energy is:
The change in potential energy of a 3.0 kilograms backpack carried up the stairs.
b) If we know that ,
and
, then the change in potential energy is:
The change in potential energy of a persona with weight 650 newtons that descends the stairs is -2665 joules.
Answer:
Explanation:
Let consider the following system, which is described in the image attached below and two reference axis, one parallel and the other perpendicular to the direction of motion. The corresponding equations of equilibrium are described herein:
The acceleration of the bowling ball at the lowest point occurs at
