Families or ____ of elements are similar in their number of valence electrons

Data:

____ [38]

a. The speed of the tsunami at ocean depth of 8000 m is 1,019.66 km/h.

b. The speed of the tsunami at ocean depth of 3500 m is 660.75 km/h.

c. The speed of the tsunami at ocean depth of 70 m is 89.66 km/h.

d. The speed of the tsunami at ocean depth of 5 m is 30.625 km/h.

<h3>Speed of the tsunami at the given depths</h3>

The speed of the tsunami is calculated from method of extrapolation or interpolation as shown below;

<h3>Speed at 8000 meters</h3>

8000 m -------- ?

7000 m -------- 943 km/h

4000 m -------- 713 km/h

(8000 - 7000)/(7000 - 4000) = (? - 943)/(943 - 713)

0.3333 = (? - 943)/230

230(0.3333) = ? - 943

76.66 = ? - 943

? = 1,019.66 km/h

<h3>Speed at 3500 m</h3>

4000 m ---------- 713 km/h

3500 m ---------- ?

2000 m ----------- 504 km/h

(4000 - 3500)/(4000 - 2000) = (713 - ?) / (713 - 504)

0.25 = (713 - ?) /209

0.25(209) = 713 - ?

52.25 = 713 - ?

? = 660.75 km/h

<h3>Speed at 70 m</h3>

200 m ------ 159 km/h

70 m --------- ?

50 m ------- 79 km/h

(200 - 70)/(200 - 50) = (159 - ?)/(159 - 79)

0.8667 = 159 - ? / 80

80(0.8667) = 159 - ?

69.336 = 159 - ?

? = 89.66 km/h

<h3>Speed at 5 meters</h3>

50 m ------- 79 km/h

10 m --------- 36 km/h

5 m ---------- ?

(50 - 5)/(50 - 10) = (79 - ?)/(79 - 36)

1.125 = 79 - ?/43

43(1.125) = 79 - ?

48.375 = 79 - ?

? = 30.625 km/h

Learn more about speed of tsunami here: brainly.com/question/23136161

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8 0

2 years ago

A lead ball is dropped into a lake from a diving board 5.0 meters above the water. After entering the water, it sinks to the bot

xxMikexx [17]

Answer:

28.8 meters

Explanation:

We must first determine at which velocity the ball hits the water. To do so we will:

1) Assume no air resistance.

2) Use the Law of conservation of mechanical energy: E=K+P

Where

E is the mechanical energy (which is constant)

K is the kinetic energy.

P is the potential energy.

With this we have $\frac{m}{2} *v^{2} = m*g*h$

Where:

m is the balls's mass <- we will see that it cancels out and as such we don't need to know it.

v is the speed when it hits the water.

g is the gravitational constant (we will assume g=9.8 $\frac{m}{s^{2} }$ .

h is the height from which the ball fell.

Because when we initially drop the ball, all its energy is potential (and $P = - m*g*h$ ) and when it hits the water, all its energy is kinetic ( $K=\frac{m}{2} *v^{2}$ . And all that potential was converted to kinetic energy.

Now, from $\frac{m}{2} *v^{2} = m*g*h$ we can deduce that $v=\sqrt{2*g*h}$

Therefore v=9.6 $\frac{m}{s}$

Now, to answer how deep is the lake we just need to multiply that speed by the time it took the ball to reach the bottom.

So D=9.6 $\frac{m}{s}$ *3 $s$ =28.8 $m$

Which is our answer.

7 0

3 years ago

Read 2 more answers

You are leaving for a party at your cousin’s house in a city that is 150 km away. You will travel at an average rate of 50 km/hr

mrs_skeptik [129]

The distance you should cover is: S=150 km

Your average speed is: v=50 km/h

Therefore, to calculate the time you will take to cover this distance, we can use the basic relationship between space, distance and time, and we find:

$t=\frac{S}{v}=\frac{150 km}{50 km/h}=3 h$