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Thepotemich [5.8K]
3 years ago
12

Solve for x. The triangles are similar. A. 5 B. 10 C. 4 D. 8

Mathematics
1 answer:
Charra [1.4K]3 years ago
8 0

Answer:  D) 8

Work Shown:

32/24 = 2x/12

32*12 = 24*2x

384 = 48x

48x = 384

x = 384/48

x = 8

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What is the radius of a circle whose equation is X^2 plus Y^2 -10X +6 X +18=0?
frosja888 [35]

ANSWER

The radius is 4

EXPLANATION

The given equation is:

{x}^{2}  +  {y}^{2}  - 10y + 6x + 18 = 0

We complete the square to get the expression in standard form:

{x}^{2}  + 6x +  {y}^{2}  - 10y  + 18 = 0

{x}^{2}  + 6x +  9 + {y}^{2}  - 10y  + 25  =  - 18 + 9 + 25

We factor using perfect squares to get:

{(x + 3)}^{2}  +  {(y - 5)}^{2} =  16

This implies that,

{(x + 3)}^{2}  +  {(y - 5)}^{2} =   {4}^{2}

Comparing to

{(x  - h)}^{2}  +  {(y - k)}^{2} =   {r}^{2}

The radius is r=4

3 0
3 years ago
Find the length of the radius of the circle.
bearhunter [10]

Answer:

C)  6 inches

Step-by-step explanation:

(√72)² = x² + x²

72 = 2x²

72/2 = x²

36 = x²

√36 = √x²

6 = x

x = 6 inches

3 0
3 years ago
Read 2 more answers
Whats the answer to 8p squared minus 16 p=10
goblinko [34]
8p² - 16p = 10

8p² - 16p - 10 = 0      Divide through by 2

4p² - 8p - 5 = 0

Multiply first and last coefficients:  4*-5 = -20

We look for two numbers that multiply to give -20, and add to give -8

Those two numbers are 2 and -10.

Check:   2*-10 = -20         2 + -10 = -8

We replace the middle term of -8p in the quadratic expression with 2p -10p


 4p² - 8p - 5 = 0     

4p² + 2p - 10p - 5 = 0     

2p(2p + 1) - 5(2p + 1) = 0

(2p + 1)(2p - 5) = 0

2p + 1 = 0    or   2p + 5 = 0

2p = 0 -1              2p = 0 - 5

2p = -1                    2p = -5

p = -1/2                    p = -5/2

The solutions are p = -1/2  or  -5/2
7 0
4 years ago
Read 2 more answers
At an airport, it cost 7 to park for one hour and 5 per hour for each additional hour.Let x represent the number hours parked.wr
kompoz [17]
The cost of parking is an initial cost plus an hourly cost.
The first hour costs $7.
You need a function for the cost of more than 1 hour,
meaning 2, 3, 4, etc. hours.
Each hour after the first hour costs $5.

1 hour: $7
2 hours: $7 + $5                  = 7 + 5 * 1          = 12
3 hours: $7 + $5 + $5          = 7 + 5 * 2          = 17
4 hours: $7 + $5 + $5 + $5  = 7 + 5 * 3          = 22

Notice the pattern above in the middle column.
The number of $5 charges you add is one less than the number of hours.
For 2 hours, you only add one $5 charge.
For 3 hours, you add two $5 charges.

Since the number of hours is x, according to the problem, 1 hour less than the number of hours is x - 1.

The fixed charge is the $7 for the first hour.
Each additional hour is $5, so you multiply 1 less than the number of hours,
x - 1, by 5 and add to 7.

C(x) = 7 + 5(x - 1)

This can be left as it is, or it can be simplified as

C(x) = 7 + 5x - 5

C(x) = 5x + 2

Answer: C(x) = 5x + 2

Check:
For 2 hours: C(2) = 5(2) + 2 = 10 + 2 = 12
For 3 hours: C(3) = 5(3) + 2 = 15 + 2 = 17
For 4 hours: C(3) = 5(4) + 2 = 20 + 2 = 22
Notice that the totals for 2, 3, 4 hours here
are the same as the right column in the table above.
6 0
4 years ago
Help me it’s urgent
Ket [755]

Answer:

a_1 = -\dfrac{3}{4}

Step-by-step explanation:

a_1 \times r = a_2

a_1 \times r^2 = a_3

a_1 \times r^3 = a_4

...

a_1 \times r^8 = a_9

\dfrac{a_9}{a_4} = \dfrac{a_1 \times r^8}{a_1 \times r^3} = \dfrac{-196}{6}

r^5 = -32

r = -2

a_1 \times r^3 = a_4

a_1 \times (-2)^3 = 6

a_1 = \dfrac{6}{-8}

a_1 = -\dfrac{3}{4}

3 0
4 years ago
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