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Nimfa-mama [501]
3 years ago
14

I neeeed helppp plz

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
7 0

Answer:

7. y=x-2, 8. y=3/2x+4, 9.  y=-3/4x+8, 10. y=2x-7, 11. y=-5x-3, 12. y=4x-5,             13. y=-3x-1, 14. y=-1/2x+1, 15. y=3/2x+4

Step-by-step explanation:

First you have to plug in the points into y2-y1/x2-x1. This would make it      -2-0/0+1. Simplify this to get -2/1 which is -2. This makes the slope -2. Then plug in the slope into point intercept form y-y1=m(x-x1) where m is the slope. This time, I will use the point (0,-2). Therefore, the equation will be y+2=1(x-0) which is equal to y+2 =x-0 which is equal to y=x-2.

This is how you do all of the problems. For problem 13-15, you know that f(0)=-1 is (0,-1) and f(3)=-10 is (3,-10). Then you can solve the problems. I will not explain every single problem but will give you the answers.

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Ilya [14]

Answer:

x^6+3x^3+3+\dfrac{1}{x^3}

Step-by-step explanation:

We can use the pascal triangle to find the coefficients of the expasion of the cube. It holds that

(x^2 + \dfrac{1}{x})^3=(x^2)^3+3(x^2)^2\dfrac{1}{x}+3x^2(\dfrac{1}{x})^2+(\dfrac{1}{x})^3\\\\=x^6+3x^4\dfrac{1}{x}+3x^2\dfrac{1}{x^2}+\dfrac{1}{x^3}\\\\=x^6+3x^3+3+\dfrac{1}{x^3}

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Step-by-step explanation:

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Step-by-step explanation:

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Write 5(6x+4)-2(5x-2) in the form a(bx+c) where a,b and c integers and a>1
Tamiku [17]

Answer:

<h2>4(5x + 6)</h2>

Step-by-step explanation:

5(6x+4)-2(5x-2)\qquad\text{use distributive property}\ a(b+c)=ab+ac\\\\=(5)(6x)+(5)(4)+(-2)(5x)+(-2)(-2)\\\\=30x+20-10x+4\qquad\text{combine like terms}\\\\=(30x-10x)+(20+4)\\\\=20x+24

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