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adell [148]
3 years ago
5

Paco has a traditional health insurance plan. His deductible is $750. The level of co-insurance for his plan is 70/30 where 30 r

epresents Paco’s portion. He also has a one-time co-payment of $20. If Paco incurs a $1,000 hospital bill, determine how much money will he owe out-of-pocket for the bill.
Mathematics
2 answers:
liberstina [14]3 years ago
5 0

Answer:

the answer is $720

Step-by-step explanation:

lesya692 [45]3 years ago
4 0
<span>The traditional health insurance of Paco had a deductible of $750. Of the remaining value, his co-insurance for his plan had a policy of 70/30, the latter being his share. He also had a one-time co payment of $20. Of the $1,000 hospital bill, it will first be deducted by $750 giving only $250. Of this amount, he will pay only 30% which is equal to $75. Deducting another $20, he will pay for only $55.</span>
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Marissa's dance studio charges a monthly fee, plus a fixed amount per class.
Studentka2010 [4]

Answer:

Step-by-step explanation:

4 0
2 years ago
A particle moving in a planar force field has a position vector x that satisfies x'=Ax. The 2×2 matrix A has eigenvalues 4 and 2
andrey2020 [161]

Answer:

The required position of the particle at time t is: x(t)=\begin{bmatrix}-7.5e^{4t}+1.5e^{2t}\\2.5e^{4t}-1.5e^{2t}\end{bmatrix}

Step-by-step explanation:

Consider the provided matrix.

v_1=\begin{bmatrix}-3\\1 \end{bmatrix}

v_2=\begin{bmatrix}-1\\1 \end{bmatrix}

\lambda_1=4, \lambda_2=2

The general solution of the equation x'=Ax

x(t)=c_1v_1e^{\lambda_1t}+c_2v_2e^{\lambda_2t}

Substitute the respective values we get:

x(t)=c_1\begin{bmatrix}-3\\1 \end{bmatrix}e^{4t}+c_2\begin{bmatrix}-1\\1 \end{bmatrix}e^{2t}

x(t)=\begin{bmatrix}-3c_1e^{4t}-c_2e^{2t}\\c_1e^{4t}+c_2e^{2t} \end{bmatrix}

Substitute initial condition x(0)=\begin{bmatrix}-6\\1 \end{bmatrix}

\begin{bmatrix}-3c_1-c_2\\c_1+c_2 \end{bmatrix}=\begin{bmatrix}-6\\1 \end{bmatrix}

Reduce matrix to reduced row echelon form.

\begin{bmatrix} 1& 0 & \frac{5}{2}\\ 0& 1 & \frac{-3}{2}\end{bmatrix}

Therefore, c_1=2.5,c_2=1.5

Thus, the general solution of the equation x'=Ax

x(t)=2.5\begin{bmatrix}-3\\1\end{bmatrix}e^{4t}-1.5\begin{bmatrix}-1\\1 \end{bmatrix}e^{2t}

x(t)=\begin{bmatrix}-7.5e^{4t}+1.5e^{2t}\\2.5e^{4t}-1.5e^{2t}\end{bmatrix}

The required position of the particle at time t is: x(t)=\begin{bmatrix}-7.5e^{4t}+1.5e^{2t}\\2.5e^{4t}-1.5e^{2t}\end{bmatrix}

6 0
3 years ago
Draw a line tangent to the circle at the point (0, 4). Write an equation for this tangent line. Explain your work.PLEASE HELP
kirill [66]

Answer:

y = 1/4x + 4

Step-by-step explanation:

5 0
2 years ago
Need some help please!!​
ella [17]

Answer:

The other point on the diameter which is also on the circle is; (-3, 2)

Step-by-step explanation:

The center of the circle, also a point where the diameter crosses, is (3, 6)

The diameter touches the circle at point (9, 10)

The displacement is (9 - 3, 10 - 6) = (6, 4)

This means that we move, +6 units along the x-axis and +4 units along the y-axis , from the center of the circle in order to reach point (9, 10)

If we want to reach the other point on the diameter which also on the circle, we move -6 units along the x-axis and -4 units along the y-axis to get;

(3, 6) - (6, 4) = (-3, 2)

6 0
3 years ago
Madam Siti bought the same lengths of red and yellow ribbons. After she used 836 cm of the red ribbon, the length of the yellow
Yuliya22 [10]

Answer: 1045 cm of red ribbon and 1045 cm of yellow ribbon

<u>Step-by-step explanation:</u>

Let R represent the amount red ribbon and Y represent the amouont of yellow ribbon.

  • bought the same lengths of red and yellow: R = Y
  • after used 286 of red, yellow is 5 times the remaining red; 5(R - 836) = Y

Use substitution method to solve:

5(R - 836) = R

5R - 4180 = R   <em>distributed 5 on the left side</em>

4R - 4180 = 0   <em>subtracted R from both sides</em>

4R = 4180         <em>added 4180 to both sides</em>

R = 1045         <em>divided both sides by 4</em>


5 0
3 years ago
Read 2 more answers
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