Ummmm i think you probly can reaserch it on google
Answer:
1027.62 g
Explanation:
For :-
Mass of = 296.1 g
Molar mass of = 27.66 g/mol
The formula for the calculation of moles is shown below:
Thus,
From the balanced reaction:-
1 mole of react with 3 moles of oxygen
Thus,
10.705 mole of react with 3*10.705 moles of oxygen
Moles of oxygen = 32.115 moles
Molar mass of oxygen gas = 31.998 g/mol
<u>Mass = Moles * Molar mass = 32.115 * 31.998 g = 1027.62 g</u>
Potential difference is energy per coloumb of charge so energy = vq
energy = 1.5 * 9000 = 13500 J
The principal quantum number, <span>nn</span>, designates the principal electron shell. Because n describes the most probable distance of the electrons from the nucleus, the larger the number n is, the farther the electron is from the nucleus, the larger the size of the orbital, and the larger the atom is. n can be any positive integer starting at 1, as <span><span>n=1</span><span>n=1</span></span> designates the first principal shell (the innermost shell). The first principal shell is also called the ground state, or lowest energy state. This explains why <span>nn</span> can not be 0 or any negative integer, because there exists no atoms with zero or a negative amount of energy levels/principal shells. When an electron is in an excited state or it gains energy, it may jump to the second principle shell, where <span><span>n=2</span><span>n=2</span></span>. This is called absorption because the electron is "absorbing" photons, or energy. Known as emission, electrons can also "emit" energy as they jump to lower principle shells, where n decreases by whole numbers. As the energy of the electron increases, so does the principal quantum number, e.g., n = 3 indicates the third principal shell, n = 4 indicates the fourth principal shell, and so on.
Answer:
moles of camphor = 0.0522 moles
Explanation:
<u>Data:</u>
MW camphor= 152 g/mol
V solution = 1.32 L
M solution = 6.01 M
moles solute = ?
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To calculate the moles of camphor, you must first know the grams of solute (camphor) that exist in the solution, this is calculated from the molarity equation:
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From there the grams of the solute (camphor) are cleared:
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Then by means of the molecular weight (MW) equation the moles can be obtained: