The following reaction was carried out in a 3.00 L reaction vessel at 1100 K:
1 answer:
Answer:
Explanation:
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In this case, since the given undergoing chemical reaction is correctly balanced, the reaction quotient is computed as well as the equilibrium constant but in terms of the given concentrations that are:
In such a way, the reaction quotient turns out:
Taking into account that carbon is not included since it is solid.
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Explanation:
Entropy means the amount of randomness present within the molecules of the body of a substance.
Relation between entropy and microstate is as follows.
S =
where, S = entropy
= Boltzmann constant
= number of microstates
This equation only holds good when the system is neither losing or gaining energy. And, in the given situation we assume that the system is neither gaining or losing energy.
Also, let us assume that = 1, and
= 0.833
Therefore, change in entropy will be calculated as follows.
=
=
=
or, =
Thus, we can conclude that the entropy change for a particle in the given system is J/K particle.
Answer: 1.
2. 3 moles of : 2 moles of
3. 0.33 moles of : 0.92 moles of
4. is the limiting reagent and
is the excess reagent.
5. Theoretical yield of is 29.3 g
Explanation:
To calculate the moles :
The balanced chemical equation is:
According to stoichiometry :
3 moles of require = 2 moles of
Thus 0.33 moles of will require=
of
Thus is the limiting reagent as it limits the formation of product and
is the excess reagent.
As 3 moles of give = 2 moles of
Thus 0.33 moles of give =
of
Theoretical yield of
Thus 29.3 g of aluminium chloride is formed.
The empirical formula of metal iodide : CoI₃(Cobalt(III) Iodide)
<h3>Further explanation</h3>13.02 g sample of Cobalt , then mol Co(MW=58.933 g/mol) :
Mass of metal iodide formed : 97.12 g, so mass of Iodine :
Then mol iodine (MW=126.9045 g/mol) :
mol ratio of Cobalt and Iodine in the compound :