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LenaWriter [7]
3 years ago
14

I’m not asking for much :(

Mathematics
2 answers:
Vinvika [58]3 years ago
8 0

Answer:

c

Step-by-step explanation:

BabaBlast [244]3 years ago
5 0

Answer:

c

Step-by-step explanation:

mcfluffythebigrubberducky

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What is 1/3 of 18? Plz help I don't know.
Aleksandr-060686 [28]
The answer to ur question is 6
4 0
3 years ago
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Melinda earns 5 minutes to play video games for every hour she spends on homework.
Law Incorporation [45]
<h2>Answer:</h2>

15 minutes

<h2>Step-by-step explanation:</h2>

For every hour of homework she gets 5 minutes of video games.

She spend 3 hours of homework.

We multiply 3*5

Answer is 15

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3 years ago
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Is this positive, negative, none or you cannot tell. Will mark CORRECT brainliest
pshichka [43]

Answer:

Positive correlation if right. Atleast consider brainlist:)

Step-by-step explanation:

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3 years ago
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F(x)=−x <br> 2<br> −7x Find f(−10)
djyliett [7]

Answer:

What's '2−7x'

Step-by-step explanation:

3 0
2 years ago
2.- Supóngase que los diámetros de los tornillos fabricados por una compañía están distribuidos normalmente con una media de 0.2
Sergio [31]

Answer:

7.30167%

Step-by-step explanation:

Usando la fórmula de puntuación z

z = (x-μ) / σ, donde x es la puntuación bruta, μ es la media de la población y σ es la desviación estándar de la población

Para x <0.20 pulgadas

z = 0.20 - 0.25 / 0.02

z = -2.5

Valor de probabilidad de Z-Table:

P (x <0.20) = 0.0062097

Para x> 0.28 pulgadas

z = 0.28 - 0.20 / 0.02

z = 1.5

Valor de probabilidad de Z-Table:

P (x <0.28) = 0.93319

P (x> 0.28) = 1 - P (x <0.28) = 0.066807

La probabilidad de que se produzcan tornillos defectuosos cuando el tornillo se considera defectuoso si su diámetro es inferior a 0.20 pulgadas o superior a 0.28 pulgadas es

P (x <0.20) + P (x> 0.28)

= 0.0062097 + 0.066807

= 0.0730167

Conversión a porcentaje

= 0.0730167 × 100

= 7.30167%

El porcentaje de tornillos defectuosos producidos es

7.30167%

3 0
2 years ago
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