Answer:
<em>C. 1/(4^10)</em>
Step-by-step explanation:
<h2>Let's break it down: 4^-2 = 1/(4^2)</h2><h2>(1/(4^2))^5 = (1^5)/(4^2)^5 = 1/(4^10)</h2>
Answer: 490 grams of the first alloy should be used.
30 grams of the second alloy should be used.
Step-by-step explanation:
Let x represent the weight of the first alloy in grams that should be used.
Let y represent the weight of the second alloy in grams that should be used.
A chemist has two alloys, one of which is 15% gold and 20% lead. This means that the amount of gold and lead in the first alloy is
0.15x and 0.2x
The second alloy contains 30% gold and 50% lead. This means that the amount of gold and lead in the second alloy is
0.3y and 0.5y
If the alloy to be made contains 82.5 g of gold, it means that
0.15x + 0.3y = 82.5 - - - - - - - - - - - -1
The second alloy would also contain 113 g of lead. This means that
0.2x + 0.5y = 113 - - - - - - - - - - - - -2
Multiplying equation 1 by 0.2 and equation 2 by 0.15, it becomes
0.03x + 0.06y = 16.5
0.03x + 0.075y = 16.95
Subtracting, it becomes
- 0.015y = - 0.45
y = - 0.45/- 0.015
y = 30
Substituting y = 30 into equation 1, it becomes
0.15x + 0.3 × 30 = 82.5
0.15x + 9 = 82.5
0.15x = 82.5 - 9 = 73.5
x = 73.5/0.15
x = 490
Answer:
The correct answer is €10.00
Step-by-step explanation:
50% of 40 is 20. 50% of 50 is 25, so what you do is just take 20 and multiply that by 0.5 or you can just take 40 and multiply that by 0.25.
I really hope this helps you out!
So first let’s put g(f(x)) together by putting f(x) for every x in g(x)
We get g(f(x))=3(3/4x+3)+4 which is the selling price equation
Then you plug in 20 to find the selling price for 20 muffins.
g(f(x))=3(3/4(20)+3)+4
g(f(x))=3(60/4+3)+4
g(f(x))=3(18)+4
g(f(x))=54+4
g(f(x))=58
So the selling price will be $58 for 20 muffins.
