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3 years ago

PLEASE HELP PLEASEEEE

Mathematics

1 answer:

Maurinko [17]3 years ago

3 0

Answer:

For A = tan = 20/14

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Describe and correct the error a student made finding the intercepts of the graph of the line 4x-6y=12

Bingel [31]

Answer:the error is when 6y=12

Step-by-step explanation:

the original problem says 4x-6y=12

so when you get rid of the 4x, it should still be -6y not positive

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3 years ago

Y = 4 + 5x what is the missing value

shutvik [7]

Answer: -1

Step-by-step explanation:

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3 years ago

Find two numbers, if their sum is −11 and their difference is 41

snow_tiger [21]

The larger one is (-11 + 41)/2 = 15.

The smaller one is (-11 -41)/2 = -26.

_____

For two numbers a and b with sum s and difference d, you can write the equations

$a+b=s\\a-b=d$

Then adding the equations and dividing that sum by 2, you get

$(a+b)+(a-b)=(s)+(d)\\2a=s+d\\a=\dfrac{s+d}{2}$

You can subtract the second eqution from the first and get a similar result for the smaller number

$(a+b)-(a-b)=(s)-(d)\\2b=s-d\\b=\dfrac{s-d}{2}$

These are the formulas we used above.

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4 years ago

The length of a rectangular field is 75 yards. This is 3 yards more than twice the width. How wide is the field?

spin [16.1K]

$length=75yd\\\\width=w\\\\2w+3=75\ \ \ \ \ \ |subtract\ 3\ from\ both\ sides\\\\2w=72\ \ \ \ \ \ |divide\ both\ sides\ by\ 2\\\\\boxed{w=36\ (yd)}$

5 0

3 years ago

A population of values has a normal distribution with μ = 247 and σ = 62.2. You intend to draw a random sample of size n = 16. (

nadya68 [22]

Answer:

a) $z = \frac{295.2-247}{62.2}=0.772$

And using the normal distribution table or excel we got:

$P(Z>0.772) = 1-P(Z$

b) $z = \frac{295.5 -247}{\frac{62.2}{\sqrt{16}}}= 3.119$

And we can use the normal standard table or excel in order to find the probability and we got:

$P(z>3.119) =1-P(Z$

Step-by-step explanation:

For this case we know that the random variable of interest is normally distributed with the following parameters:

$X \sim N (\mu = 247, \sigma =62.2)$

Part a

We want to find this probability:

$P(X>295.2)$

And we can use the z score formula given by:

$z = \frac{X-\mu}{\sigma}$

Replacing we got:

$z = \frac{295.2-247}{62.2}=0.772$

And using the normal distribution table or excel we got:

$P(Z>0.772) = 1-P(Z$

Part b

We select a random sample of size n = 16 and we try to find this probability:

$P(\bar X >295.2)$

And we can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And replacing we got:

$z = \frac{295.5 -247}{\frac{62.2}{\sqrt{16}}}= 3.119$

And we can use the normal standard table or excel in order to find the probability and we got:

$P(z>3.119) =1-P(Z$

8 0

3 years ago