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Alexandra [31]
4 years ago
13

Where do the numbers go and explain how you decided where to place 1/4,6/8,1 1/7

Mathematics
1 answer:
-Dominant- [34]4 years ago
8 0

Answer:

Step-by-step explanation:

      1/4                 1/2            3/4          8/8.                           1 2/4             1 7/8

__________________________________________________________

0.                                                            1.                                                           2                  

This is not extremely accurate

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What is 8.05 × 10-5 in standard notation?
padilas [110]

Answer:

0.0000805 0.00000805 805,000 8,050,000. i think

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
A gumball has a diameter that is 66 mm. The diameter of the gumball's spherical hollow core is 58 mm. What is the volume of the
grigory [225]

Answer:

Volume of gumball without including its hollow core is 48347.6 cubic mm.

Step-by-step explanation:

Given:

Diameter of Gumball = 66 mm

Since radius is half of diameter.

Radius of gumball = \frac{diameter}{2}=\frac{66}{2} =33 \ mm

Now We will first find the Volume of Gumball.

To find the Volume of Gumball we will use volume of sphere which is given as;

Volume of Sphere = \frac{4}{3}\pi r^3

Now Volume of Gumball = \frac{4}{3}\times3.14 \times (33)^3 = 150456.24 \ mm^3

Also Given

Diameter of gumball's spherical hollow core = 58 mm

Since radius is half of diameter.

Radius of gumball's spherical hollow core = \frac{diameter}{2}=\frac{58}{2} =29 \ mm

Now We will find the Volume of gumball's spherical hollow core.

Volume of Sphere = \frac{4}{3}\pi r^3

So Volume of gumball's spherical hollow core = \frac{4}{3}\times3.14 \times (29)^3 = 102108.61 \ mm^3

Now We need to find volume of the gumball without including its hollow core.

So, To find volume of the gumball without including its hollow core we would Subtract Volume of gumball spherical hollow core from Volume of Gumball.

volume of the gumball without including its hollow core = Volume of Gumball - Volume of gumball's spherical hollow core = 150456.24\ mm^3 - 102108.61\ mm^3 = 48347.63\ mm^3

Rounding to nearest tenth we get;

volume of the gumball without including its hollow core = 48347.6\ mm^3

Hence Volume of gumball without including its hollow core is 48347.6 cubic mm.

8 0
3 years ago
1. Use a ratio box to solve this problem. Tammy saved nickels and
Mice21 [21]

Answer:

245

Step-by-step explanation:

let 'c' = total coins

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2c = 490

c = 245

7 0
3 years ago
Scores on a certain IQ test are knownto have a mean of 100. A random sample of 43 students attend a series of coaching classes b
NeX [460]

Answer:

Part 1

Type II error

Part 2

No ; is not ; true

Step-by-step explanation:

Data provided in the question

Mean = 100

The Random sample is taken = 43 students

Based on the given information, the conclusion is as follows

Part 1

Since it is mentioned that the classes are successful which is same treated as a null rejection and at the same time it also accepts the alternate hypothesis

Based on this, it is a failure to deny or reject the false null that represents type II error

Part 2

And if the classes are not successful so we can make successful by making type I error and at the same time type II error is not possible

Therefore no type II error is not possible and when the null hypothesis is true the classes are not successful

6 0
3 years ago
Eight more than the product of some number cubed and two
Greeley [361]
 8+ the product of 2 and a number to the third power, what it means 2×m cubed. So it is 8+2m (cubed)
4 0
3 years ago
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