Answer:
-5/ (x^19 * y^12)
Step-by-step explanation:
-15x^-10 * y ^ -3 * x^-9 * y^-9/3 (It's writing it like this.)
15 and 3 have a GCF of 3.
-5x^-10 * y^-3 * x^-9 * y^-9/1
Reduce similar occurrences. *twice in a row*
-5x^(-10 + (-9)) * y^(-3 + (-9))/1
Remove extra signs *twice in a row*
-5x^(-10 - 9) * y^(-3 - 9)/1
Remove extraneous 1.
-5x^(-10 - 9) * y^(-3 - 9)
Add integers.
-5x^-19 * y^-12
Negative powers change multiplication to division.
-5 / (x^19 * y^12) is the final answer.
Even with that, the simplified answer wouldn't have negative exponents because of the negative powers rule.
2(n+7) =3n
n = 14
<span>n = 14</span>
so, we have two 54x18 rectangles, so their perimeter is simply all those units added together, 54+54+54+54+18+18+18+18 = 288.
we know the circle's diameter is 1.5 times the width, well, the width is 18, so the diameter of the circle must be 1.5*18 = 27.
![\bf \stackrel{\textit{circumference of a circle}}{C=d\pi }~~ \begin{cases} d=diameter\\[-0.5em] \hrulefill\\ d=27 \end{cases}\implies C=27\pi \implies C=\stackrel{\pi =3.14}{84.78} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{perimeter of the rectangles}}{288}~~~~+~~~~\stackrel{\textit{perimeter of the circle}}{84.78}~~~~=~~~~372.78](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7Bcircumference%20of%20a%20circle%7D%7D%7BC%3Dd%5Cpi%20%7D~~%20%5Cbegin%7Bcases%7D%20d%3Ddiameter%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20d%3D27%20%5Cend%7Bcases%7D%5Cimplies%20C%3D27%5Cpi%20%5Cimplies%20C%3D%5Cstackrel%7B%5Cpi%20%3D3.14%7D%7B84.78%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Bperimeter%20of%20the%20rectangles%7D%7D%7B288%7D~~~~%2B~~~~%5Cstackrel%7B%5Ctextit%7Bperimeter%20of%20the%20circle%7D%7D%7B84.78%7D~~~~%3D~~~~372.78)
Answer:
30/552
Step-by-step explanation:
In order to solve this problem you need to multiply the probability of getting grape for the first gumball with the probability of getting grape for the second gumball. Since there are 6 grape gumballs and a total of 24 gumballs (6*4). Then the probability of getting grape for the firs one is

Now there are only 5 grape gumballs available and one less in the total supply, therefore the probability of getting grape in the second try is

Finally we multiply them together to find the probability of getting two grapes in a row.
= 