An airplane is flying in a direction of 75° north of east at a constant flight speed of 300 miles per hour. The wind is blowing
due west at a speed of 25 miles per hour. What is the actual direction of the airplane? Round your answer to the nearest tenth. Show your work. PLS PLS PLSPLS HELP URGANT
We resolve the speed of the plane into horizontal and vertical components respectively as 300cos75° and 300sin75° respectively. Since the wind blows due west at a speed of 25 miles per hour, its direction is horizontal and is given by 25cos180° = -25 mph. We now add both horizontal components to get the resultant horizontal component of the airplane's speed.
The vertical component of its speed is 300sin75° since that's the only horizontal motion of the airplane. So the resultant vertical component of the airplane's speed is 300sin75° = 289.778 mph
The direction of the plane, Ф = tan⁻¹(vertical component of speed/horizontal component of speed)
100%/x%=300/60(100/x)*x=(300/60)*x - we multiply both sides of the equation by x100=5*x - we divide both sides of the equation by (5) to get x100/5=x 20=x x=20 now we have: 60 is 20% of 300
