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Agata [3.3K]
3 years ago
7

Lauren earns $13 per hour at her after school job. If she has worked 64 hours at this job, how much has Lauren earned total?

Mathematics
1 answer:
disa [49]3 years ago
8 0

Answer: $832

Step-by-step explanation:

Lauren earned $13 per hour and she worked for 64 hours.

Total she would make is:

= 13 * 64

= $832

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Which is equivalent to 80^1/4x ?
Anestetic [448]

Answer: This expression is equivalent to 3^x

Step-by-step explanation: In this question the important concept is to write 80 in exponential form and multiply the exponents.

=80^1/4x

=(3^4)^1/4x

=3^x

4 0
3 years ago
2) If a remote car cost $28.00 at wholesale, what is the retail price if it is marked up by 25%? *
Juliette [100K]

Answer:

$35

Step-by-step explanation:

25% ×28 =7.

28 + 7 = 35

7 0
3 years ago
Read 2 more answers
Help please, I need it
OlgaM077 [116]

Answer:

  2)  c)  (x-3)² + (y+2)² = 25

  5)  x^2 +y^2 -8x -16y +54 = 0

  6)  x^2 +y^2 -10x -12y +36 = 0

Step-by-step explanation:

2) The standard form equation for a circle is ...

  (x -h)^2 +(y -k)^2 = r^2

You are given the center: (h, k) = (3, -2) and a point on the circle. So, the equation will be ...

  (x -3)^2 +(y +2)^2 = r^2

Since we know a point on the circle we know that ...

  (7 -3)^2 +(1 +2)^2 = r^2 = 16 +9 = 25

So, the circle's equation is ...

  (x -3)^2 +(y +2)^2 = 25 . . . . . matches choice C

__

5) As in the previous problem, the standard form equation is ...

  (x -4)^2 +(y -8)^2 = (-1-4)^2 +(7-8)^2 = 25+1 = 26

To put this in general form, we need to subtract 26 and eliminate parentheses.

  x^2 -8x +16 +y^2 -16y +64 -26 = 0

  x^2 +y^2 -8x -16y +54 = 0

__

6) A circle tangent to the y-axis will have a radius equal to the x-value of the center point.

  (x -5)^2 +(y -6)^2 = 5^2

  x^2 -10x +25 +y^2 -12y +36 = 25

  x^2 +y^2 -10x -12y +36 = 0

8 0
3 years ago
A Boxer. needs to lose 3 1/2 kg in a month to be able to complete as a flyweight. In three weeks he lowers his weight from 55.5
Airida [17]

Answer: The boxer lose 1.8 kg in the final week to get able to compete as a flyweight.

Step-by-step explanation:

Since we have given that

Quantity of weight a boxer needs to lose in a month is given by

3\frac{1}{2}\ kg\\\\=\frac{7}{2}\ kg=3.5\ kg

In 3 months, he lowers his weight from 55.5 kg to 53.8 kg.

So, Quantity of weight he lose in three months is given by

55.5-53.8\\\\=1.7\ kg

Number of kilograms the boxer lose in the final week to be able to compete as a flyweight is given by

3.5-1.7\\\\=1.8\ kg

Hence, the boxer lose 1.8 kg in the final week to get able to compete as a flyweight.

4 0
3 years ago
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Find the linear equations written in standard form. Select all that apply. x + y = –1 –3x = y
Kryger [21]

The correct answers are :

x + y = -1

x + 4y = 0

8x - 3y = 20

8 0
3 years ago
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