Given that: a = acceleration = (4i^ + 3j^) m/s^2
Using the following relations:
a = dv/dt
v = <span>∫ a dt
such that:
</span>v = ∫ (<span>4i^ + 3j^</span>) dt + C
v = (4t + Cx)i^ + (3t + Cy)j^
Therefore:
Vx = 4t + Cx
Vy = 3t + Cy
At t = 0, Cx = Cy = 0
Finally:
Vx = 4t
Vy = 3t
Answer:
64
Step-by-step explanation:
To complete the square
add ( half the coefficient of the b- term )² to b² + 16b
b² + 2(8)b + 8²
= b² + 16b + 64 = (b + 8)²
<span>Round $783.85 to the nearest $1,000.00,
</span>$1000.00 is your answer
Step-by-step explanation:
