Y= 18 gallons-2(h)
y is what you're trying to find out and since there are 18 gallons in the tank after every hour you would have 2 less gallons. So, you can multiply how many hours he's been driving by the 2 gallons and subtract it from 18
I used a little trig, the opposite and adjacent were being used so I used tan... I used it to find h and then plugged it in the a=bh
A) We want to know when h=10 so
10=-16t^2+40t+3
16t^2-40t+7=0
Using the quadratic formula:
t=(40±√1152)/32
t≈0.189 and 2.311 seconds
So it is at 10 ft twice, about 2/10 of a second when it is rising and at 2 3/10 of a second when it is falling...
b.
The maximum height of the ball is when velocity is equal to zero, or dh/dt=0
dh/dt=-32t+40, dh/dt=0 when 32t=40, t=40/32=5/4=1.25 seconds
h(1.25)=28ft
So the maximum height of the ball occurs after 1.25 seconds and reaches a height of 28 feet.
Answer:
6 apples
Step-by-step explanation:
Answer:
Step-by-step explanation:
the triangle with 9 as a side is a 45,45, 90 triangle. so there for x and 9 are congruent. Thus. x=9
