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3 years ago

5

Three of the four points below are on the graph of a proportional relationship between the variables x and y. Which point is NOT

on the graph(0,0)
(1,5)
(2,6)
(3,15)?

1 answer:

lesya [120]3 years ago

4 0

Answer:

I think 2,6

Step-by-step explanation: X5

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2x^2- 5x + 6 when x = -2

yarga [219]

Answer:

Step-by-step explanation:

x= -2

2x² - 5x + 6 = 2(-2)² - 5*(-2) + 6

= 2*4 + 10 + 6

= 8 + 10 + 6

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2 years ago

???!!???????????????????

natita [175]

The solution's something you can really easily pick up, I promise.

The solution is simply the point where the two lines connect.

In this case, it's (2,5). (x,y)

Hope this helped!

(Khan Academy is a great resource.)

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Nastasia [14]

Answer:

Ummm

Step-by-step explanation:

Im confused

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2 years ago

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Aliun [14]

Answer:

See explanation

Step-by-step explanation:

Simplify left and right parts separately.

<u>Left part:</u>

$\left(1+\dfrac{1}{\tan^2A}\right)\left(1+\dfrac{1}{\cot ^2A}\right)\\ \\=\left(1+\dfrac{1}{\frac{\sin^2A}{\cos^2A}}\right)\left(1+\dfrac{1}{\frac{\cos^2A}{\sin^2A}}\right)\\ \\=\left(1+\dfrac{\cos^2A}{\sin^2A}\right)\left(1+\dfrac{\sin^2A}{\cos^2A}\right)\\ \\=\dfrac{\sin^2A+\cos^2A}{\sin^2A}\cdot \dfrac{\cos^2A+\sin^A}{\cos^2A}\\ \\=\dfrac{1}{\sin^2A}\cdot \dfrac{1}{\cos^2A}\\ \\=\dfrac{1}{\sin^2A\cos^2A}$

<u>Right part:</u>

$\dfrac{1}{\sin^2A-\sin^4A}\\ \\=\dfrac{1}{\sin^2A(1-\sin^2A)}\\ \\=\dfrac{1}{\sin^2A\cos^2A}$

Since simplified left and right parts are the same, then the equality is true.

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3 years ago

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Answer:

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Step-by-step explanation:

The inverse of In is e

If In 0.2 = -1.6094

Then e^-1.6094 = 0.2

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3 years ago