The order of operations is used to order numerical expressions
Answer:
Step-by-step explanation:
The equation 
represents the discriminant of a quadratic. It is the part taken from under the radical in the quadratic formula.
For any quadratic:
- If the discriminant is positive, or greater than 0, the quadratic has two solutions
- If the discriminant is equal to 0, the quadratic has one distinct real solution (the solution is repeated).
- If the discriminant is negative, or less than 0, the quadratic has zero solutions
In the graph, we see that the equation intersects the x-axis at two distinct points. Therefore, the quadratic has two solutions and the discriminant must be positive. Thus, we have 
.
Answer:
I think 3
Step-by-step explanation:
i think 3
for real this time
Answer:
Step-by-step explanation:
The principal was compounded monthly. This means that it was compounded 12 times in a year. So
n = 12
The rate at which the principal was compounded is 4%. So
r = 4/100 = 0.04
The formula for compound interest is
A = P(1+r/n)^nt
A = total amount in the account at the end of t years. The total amount is given as $100000.
1) When t is 1,
100000 = P(1+0.04/12)^12×1
100000 = P(1+0.0033)^12
100000 = P(1.0033)^12
P = 100000/1.04
P = $96154
2) When t is 10
100000 = P(1+0.04/12)^12×10
100000 = P(1+0.0033)^120
100000 = P(1.0033)^120
P = 100000/1.485
P = $67340
3) When t is 20
100000 = P(1+0.04/12)^12×20
100000 = P(1+0.0033)^240
100000 = P(1.0033)^240
P = 100000/2.2
P = $45455
4) When t is 30
100000 = P(1+0.04/12)^12 × 30
100000 = P(1+0.0033)^360
100000 = P(1.0033)^360
P = 100000/3.274
P = $30544
5) When t is 40
100000 = P(1+0.04/12)^12 × 40
100000 = P(1+0.0033)^480
100000 = P(1.0033)^480
P = 100000/4.862
P = $20568
6)When t is 50
100000 = P(1+0.04/12)^12 × 50
100000 = P(1+0.0033)^600
100000 = P(1.0033)^600
P = 100000/7.22
P = $13850
