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3 years ago

Two lines, E and F, are represented by the equations given below.

Mathematics

2 answers:

melisa1 [442]3 years ago

7 0

Answer:

⇒ 5x + 5y = 40.

There are infinitely many solutions.

shusha [124]3 years ago

6 0

Although you have not included the statements about the solution to the set of the given equations, I can explain you what happen with that system.

You can arrive to the same conclusion by any method of solution of systems that you like.

The quickest in this case, is to multiply the equation of the lIne F by 5.

That leads to: 5 (x + y) = 5(8)

⇒ 5x + 5y = 40.

Now you can realize that the two representations (equations) correspond to the same line.

That means that there are infinite solutions, this is infinity values of x and y meet both equations.

If you graph line E and line F they overlap in the entire domain, so the graphing method also tells you that you cannot find one solution but infinite soluttions.

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Find the second decile of the following data set 24, 64, 25, 40, 45, 34, 14, 26, 28, 24, 58, 51 D2 =

Sergio039 [100]

Answer:

D2 = 24

Step-by-step explanation:

given is a data set as

24, 64, 25, 40, 45, 34, 14, 26, 28, 24, 58, 51

We have to find the second decile for the above

Arranging in ascending order we get

14, 24, 24, 25,26,28, 34, 40, 45, 51, 58, 64

2nd decile is equal to 20th percentile

20th percentile formula entry appearing which sorts 20% below and 80% above.

i.e. (20%*(14+1)) = 3rd entry

Thus 20th percentile is24.

D2 = 24

7 0

3 years ago

Of the Students that attended Roosevelt Elementary 6/8 of the school play a sport. Of the students are playing a sport 3/5 of th

soldier1979 [14.2K]

Answer:

$\frac{9}{20}$ students.

Step-by-step explanation:

We have been given that of the students that attended Roosevelt Elementary 6/8 of the school play a sport. Of the students are playing a sport 3/5 of the students are also involved in the drama club.

To find the students are both play a sport and a part of the drama club, we need to find 3/5 part of 6/8 as:

$\text{Students who play a sport and a part of the drama club}=\frac{6}{8}\times \frac{3}{5}$

$\text{Students who play a sport and a part of the drama club}=\frac{3}{4}\times \frac{3}{5}$

$\text{Students who play a sport and a part of the drama club}=\frac{3\times 3}{4\times 5}$

$\text{Students who play a sport and a part of the drama club}=\frac{9}{20}$

Therefore, $\frac{9}{20}$ students play sport and part of the drama club.

5 0

3 years ago

Need help :)<br><br><br><br> pleaseeeeeee :(

gayaneshka [121]

Answer: $x\geq 88$

This means that he has to save at least $88 or more to have enough money.

Step-by-step explanation:

He has $37 and he needs to save more (+) but we don't know how much more that is, so that's why that is our unknown value. (x). The sum of them has to be at least 125 or greater.

$37+x\geq 125$