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anygoal [31]
3 years ago
15

Jackie has a maximum of $450 to spend on shirts and jeans. The shirts she wants to buy are $12 each, including tax. The jeans sh

e wants to buy are $27 each, including tax. What is an inequality that represents all possible combinations of s, the number of shirts, and j, pairs of jeans, Jackie can buy
Mathematics
1 answer:
Sloan [31]3 years ago
4 0

Answer: 12s+27j≤450

Step-by-step explanation:

From the question, we are informed that Jackie has a maximum of $450 to spend on shirts and jeans and that the shirts she wants to buy are $12 each, including tax while the jeans she wants to buy are $27 each, including tax.

The inequality that represents all possible combinations of s, the number of shirts, and j, pairs of jeans, Jackie can buy will be:

= 12s+27j≤450

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3 years ago
What is the area of this polygon?
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3 years ago
A class of 28 students has 12 girls. What is the ratio of girls to boys
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What is the measure of UVW in the triangle shown? <br><br>A. 140° <br>B. 50° <br>C. 60° <br>D. 10°​
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3 years ago
Factor the expression using the two different techniques listed for Parts 1(a) and 1(b).
Natalija [7]

Answer:

9a^4 b^10(2 +3a^6 b^5)  (2 -3a^6 b^5)

see work below

Step-by-step explanation:

36a^4b^10 - 81a^16b^20

A)  find the GCF

36a^4b^10 = 4*9 a^4b^10  = 2*2*3*3 a*a*a*a*b*b*b*b*b*b*b*b*b*b

81a^16b^20= 9*9a^16b^20= 3*3*3*3* a*a*a*a*a*a*a*a*a*a*a*a*a*a*a*a                *b*b*b*b*b*b*b*b*b*b*b*b*b*b*b*b*b*b*b*b

The terms that appear in both terms is the GCF.  The terms that remain are inside the parentheses.

The GCF is 3*3 a*a*a*a*b*b*b*b*b*b*b*b*b*b

36a^4b^10 - 81a^16b^20 = 3*3 a*a*a*a*b*b*b*b*b*b*b*b*b*b *

( 2*2 - 3*3a*a*a*a*a*a*a*a*a*a*a*a b*b*b*b*b*b*b*b*b*b)

Combining like terms

36a^4b^10 - 81a^16b^20 = 9a^4b^10(4-9a^12b^10)

The expression inside the parenthesis can be factored using the difference of squares

let x^2 =4   x =2  

y^2 = 9a^12 b^10   y = 3a^6b^5

(x^2 -y^2) = (x+y)(x-y)

9a^4b^10(4-9a^12b^10) = 9a^4b^10 ( 2+3a^6b^5) ( 2-3a^6b^5)

b) difference of squares  a^2 – b^2 = (a + b)(a – b)

let a^2 = 36a^4b^10

so a = 6a^2b^5

b^2 = 81a^16b^20

b = 9a^8 b^10

a^2 – b^2 = (a + b)(a – b)

36a^4b^10 - 81a^16b^20 = (6a^2b^5 +9a^8 b^10) (6a^2b^5 -9a^8 b^10)

We can factor a 3 a^2 b^5 out of the first term

3 a^2 b^5 (2 +3a^6 b^5) (6a^2b^5 -9a^8 b^10)

3 a^2 b^5 (2 +3a^6 b^5) 3 a^2 b^5 (2 -3a^6 b^5)

Multiply the terms outside the parentheses together

9a^4 b^10(2 +3a^6 b^5)  (2 -3a^6 b^5)

4 0
3 years ago
Read 2 more answers
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