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3 years ago

Use the remainder theorem to find P(−2) for P(x) = 2x^4+2x^3−2x-4

Mathematics

2 answers:

Law Incorporation [45]3 years ago

7 0

Answer:P(2) = 2(2)³ - 2(2)²- 3

= 16 - 8 - 3

= 5

Remainder or value of P(2) = 5

Quotient = (2x³- 2x² - 3)/ x-2 = 2x² + 2x + 4

Step-by-step explanation:

LUCKY_DIMON [66]3 years ago

4 0

Answer:

P(2) = 2(2)³ - 2(2)²- 3

= 16 - 8 - 3

= 5

Remainder or value of P(2) = 5

Quotient = (2x³- 2x² - 3)/ x-2 = 2x² + 2x + 4

Step-by-step explanation:

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Read 2 more answers

21 and 22 are complementary angles.

Bumek [7]

The measure of angle 2 is $\angle 2=14^{\circ}$

Explanation:

Given that $\angle 1$ and $\angle 2$ are complementary angles.

Also, the measure of angle 1 is $\angle 1= 76^{\circ$

We need to determine the measure of $\angle 2$

Since, we know that the complementary angles add up to 90°, then the angles $\angle 1$ and $\angle 2$ add up to 90°.

Thus, we have,

$\angle 1+\angle 2=90^{\circ}$

Substituting the value of $\angle 1$ in the above expression, we have,

$76^{\circ}+\angle 2= 90^{\circ}$

Subtracting both sides by 76°, we get,

$\angle 2 = 90^{\circ}-76^{\circ}$

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3 years ago