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const2013 [10]
3 years ago
8

1 point 13. Use the order of operations to simplify the expression: 24 - 5. (-8) + (7 - 11)

Mathematics
2 answers:
kolezko [41]3 years ago
8 0

Answer:

60

Step-by-step explanation:

24 - 5(-8) + (7 - 11)

24 - -40 + (7 - 11)

24 - -40 + (-4)

24 + 40 + (-4)

24 + 36

60

ANTONII [103]3 years ago
4 0

Answer:

50

Step-by-step explanation:

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Assume the readings on thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. Find the pro
lisov135 [29]

Answer:

0.0326 = 3.26% probability that a randomly selected thermometer reads between −2.23 and −1.69.

The sketch is drawn at the end.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 0°C and a standard deviation of 1.00°C.

This means that \mu = 0, \sigma = 1

Find the probability that a randomly selected thermometer reads between −2.23 and −1.69

This is the p-value of Z when X = -1.69 subtracted by the p-value of Z when X = -2.23.

X = -1.69

Z = \frac{X - \mu}{\sigma}

Z = \frac{-1.69 - 0}{1}

Z = -1.69

Z = -1.69 has a p-value of 0.0455

X = -2.23

Z = \frac{X - \mu}{\sigma}

Z = \frac{-2.23 - 0}{1}

Z = -2.23

Z = -2.23 has a p-value of 0.0129

0.0455 - 0.0129 = 0.0326

0.0326 = 3.26% probability that a randomly selected thermometer reads between −2.23 and −1.69.

Sketch:

3 0
3 years ago
Please help ? Thanks
rjkz [21]
Try answer C or B because either one could be the right answer
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Read 2 more answers
Carter misses 25% of the free throws he attempts in a season. How many total free
Inga [223]

Answer:

so 25% of 63

63x25:100

15,75=

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79 appx

Step-by-step explanation:

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