Probability someone chosen at random will not have brown hair = 1/6
<h3>Probability of two variables</h3>
The number of girls = 15
The number of boys = 15
The total number of children = 15 + 15 = 30
Probability that someone chosen at random will have a brown hair, P(Brown hair) = 5/6
P(Brown hair) + P(Not Brown hair) = 1
5/6 + P(Not brown hair) = 1
P(not brown hair) = 1 - 5/6
P(not brown hair) = 1/6
Therefore, if someone is chosen at random, probability that they will not have brown hair = 1/6
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Answer is B.
5√3(5+2√6)=
25√3+10√18=
25√3+30√2
Note: I multiplied 10 by 3, because the prime factors of 18 are 3, 3 and 2 so I made a pair from the 3 and multipled and was left with 2.
Well I personally think and this is just my opinion or should I say answer but I think it is 16
Answer:
<em>g(x) = </em>
<em> - 3 </em>
Step-by-step explanation:
<em>g(x) = </em>
<em> - 3 </em>
I dont really the answer i am sorry i am hust writing this response to get points and ask questions