Evaluate 9C5 and 11P4 .

1 answer:

7 0

$9C5=\dfrac{9!}{5!4!}=\dfrac{6\cdot7\cdot8\cdot9}{2\cdot3\cdot4}=6\cdot7\cdot3=126\\\\
11P4=\dfrac{11!}{7!}=8\cdot9\cdot10\cdot11=7920$

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