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4 years ago

In the figure the horizontal lines are parallel and ab=bc=cd if lm =5 find jm

Mathematics

1 answer:

lisabon 2012 [21]4 years ago

8 0

By the transversal theorem, if segments on a transversal cut by parallel lines are equal, then similar segments cut by the same parallel lines on another transversal are also equal.
Therefore
JK=KL=LM=5
=>
JM=3*5=15

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Which of the following best describes the change in the range when 13 is

svetoff [14.1K]

The answer is D). It increases by 13.
If you put the numbers in order from least to greatest.. 26,34,38,49,65,75,81
You will see the 26 is the smallest number and 81 in the highest number. The range between the two numbers is 55. To find the range you take the smallest number and subtract it from the biggest number. But when you add the number 13 to the problem then26 is no longer the smallest Number because 13 replaced it. So then you take 81 and subtract 13 from it and get 68. And then you take 55 and subtract it from 68 and come with 13. Which makes the answer D.

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4 years ago

3. f(-4) – 3.g(-2) =

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I got:
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3 years ago

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alexandr402 [8]

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3 years ago

6x - 3y = -6<br> y = 2x + 2

Verizon [17]

Answer:

y=0, x=1

Step-by-step explanation:

6x-3y= -6 ...... equation 1

y =2x+2 ..... equation 2

subtract 2x from both sides

y-2x=2x-2x+2

y-2x=2

6x-3y= -6

y-2x=2

Rearrange

6x-3y= -6 ........x1

-2x +y=2............x3

6x-3y= -6

-6x +3y=2

0y=0

y=0

substitute y=0 in equation 1

6x-3xo= -6

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4 years ago

Marty made a $220 bank deposit using $10 bills and $5 bills. She gave the teller a total of 38 bills, how many $5 bills were in

Luda [366]

ANSWER: 32 five-dollar bills

======

EXPLANATION:

Let x be number of $5 bills

Let y be number of $10 bills

Since we have total of 38 bills, we must have the sum of x and y be 38

x + y = 38 (I)

Since the total amount deposited is $220, we must have the sum of 5x and 10y be 220 (x and y are just the "number of" their respective bills, so we multiply them by their value to get the total value):

5x + 10y = 220 (II)

System of equations:

$\left\{ \begin{aligned} x + y &= 38 && \text{(I)} \\ 5x + 10y &= 220 && \text{(II)} \end{aligned} \right.$

Divide both sides of equation (II) by 5 so our numbers become smaller

$\left\{ \begin{aligned} x + y &= 38 && \text{(I)} \\ x + 2y &= 44 && \text{(II)} \end{aligned} \right.$

Rearrange (I) to solve for y so that we can substitute into (II)

$\begin{aligned} x + y &= 38 && \text{(I)} \\ y &= 38 - x \end{aligned}$

Substituting this into equation (II) for the y:

$\begin{aligned} x + 2y &= 44 && \text{(II)} \\ x + 2(38 - x) &= 44\\ x + 76 - 2x &= 44 \\ -x &= -32 \\ x &= 32 \end{aligned}$

We have 32 five-dollar bills

======

If we want to finish off the question, use y = 38 - x to figure out number of $10 bills

$y = 38 - 32 = 6$

32 five-dollar bills and 6 ten-dollar bills

7 0

3 years ago