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nasty-shy [4]
3 years ago
7

Find the circumference of a circle with a radius of

Mathematics
1 answer:
Debora [2.8K]3 years ago
5 0

Answer:

What is the radius???

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Perimeter/area (triangles) ! PLZ HELP
BartSMP [9]

Answer:

50ft^2

Step-by-step explanation:

area of triangle ABC=25ft^2

both triangle have equal area and all together it makes a rectangle ABCD so ,

rect. ABCD=25+25=50FT^2

3 0
3 years ago
Read 2 more answers
Can someone please help me gladly appreciate it !
Daniel [21]
It could be The 4.0 cm would be the base and 2.8cm would be the length upwards
5 0
3 years ago
The point (a,b) is in Quadrant IV of a coordinate plane. Describe the location of the point with the coordinates of (b,a)
julia-pushkina [17]

If the point (a, b) is in Quadrant IV of a coordinate plane, then the x-coordinate of (a, b) will be positive and the y-coordinate will be negative.


EX: (5, -5)


4 0
3 years ago
Please help and explain please. would appreciate it!
Reptile [31]

Answer:

Step-by-step explanation:

A/4=72/12

A=4(72)/12

A=24 u^2

4 0
3 years ago
Read 2 more answers
Find the expression that represents the length of the hypotenuse of a right triangle whose legs measure m^2-n^2 and 2mn
My name is Ann [436]
\bf c^2=a^2+b^2\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
------\\
a=m^2-n^2\\
b=2mn
\end{cases}\\\\\\ c^2=(m^2-n^2)^2+(\underline{2mn})^2
\\\\\\
c^2=m^4-2m^2n^2+n^4+\underline{2^2m^2n^2}
\\\\\\
c^2=m^4-2m^2n^2+n^4+{4m^2n^2}
\\\\\\
c^2=m^4+2m^2n^2+n^4\impliedby \textit{perfect square trinomial}
\\\\\\
c^2=(m^2+n^2)^2\implies c=\sqrt{(m^2+n^2)^2}\implies c=m^2+n^2
7 0
3 years ago
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