A box contains four red balls and eight black balls. Two balls are randomly chosen from the box, and are not replaced. Let event
B be choosing a black ball first and event R be choosing a red ball second. What are the following probabilities?
2 answers:
The question has four different answers. The first answer is: 8/12. Second: 4/11. Third: 8/33. Fourth: 24. Hope this helps!
First answer: 8/12
Second answer: 4/11
Third answer: 8/33
fourth answer: 24 percent
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