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3 years ago

Simplify 4 (x3 – 3y2) – 2 (3x3 – 5y2)

Mathematics

1 answer:

Phoenix [80]3 years ago

5 0

$\huge \bold{answer}$

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What is the axis of symmetry for f(x) = 2x − 8x + 8? (1 point) Select one: a. x = −2 b. x = −3 c. x = 3 d. x = 2

ExtremeBDS [4]

Answer:

x=2

Step-by-step explanation:

F(x) = 2x^2 - 8x +8

Axis of symmetry lies at the x coordinate of vertex

To find x coordinate of vertex use formula

$x=\frac{-b}{2a}$

from the given f(x) , a= 2 and b = -8

Plug in all the values

$x=\frac{-(-8)}{2(2)}$

$x=\frac{8}{4}=2$

x=2

So the axis of symmetry at x=2

6 0

3 years ago

Help please..........

Ivenika [448]

Arc FE: 76°
arc DEF: 180°
arc CFD: 284°
arc DFE: 256°

4 0

3 years ago

Find the power of 3/8^3

GREYUIT [131]

(3/8)³ = (3/8)(3/8)(3/8)

Multiply across:

(3/8) x (3/8) = 9/64

Simplify:

(9/64)(3/8) = 27/512

27/512 is your fraction answer (cannot be reduced).

To find the decimal answer, divide:

27/512 = 0.05

0.05 (rounded) is your decimal answer

hope this helps

3 0

3 years ago

Factor completely 49m4 + 140m2 + 100

postnew [5]

Answer:

Step-by-step explanation:

Use identity : (a + b)² =a² + 2ab + b²

49m⁴ + 140m² + 100 = 7²(m²)² + 2 * 7m² * 10 + 10²

= (7m²)² + 2 *7m²*10 + 10²

= (7m² + 10)²

= (7m² + 10)(7m² + 10)

5 0

2 years ago

Find all critical numbers of the function <img src="https://tex.z-dn.net/?f=g%28x%29%3Dx%5E%7B%5Cfrac%7B3%7D%7B4%7D%20%7D-2x%5E%

postnew [5]

Differentiate g using the power rule:

$g'(x) = \dfrac34 x^{\frac34-1} - 2\cdot\dfrac14 x^{\frac14-1}$

$g'(x) = \dfrac34 x^{-\frac14} - \dfrac12 x^{-\frac34}$

$g'(x) = \dfrac14 x^{-\frac34} \left(3 x^{\frac12} - 2\right)$

$g'(x) = \dfrac{3\sqrt x - 2}{4 x^{\frac34}}$

The critical points of g occur where g' is zero or undefined.

We have

$g'(x) = 0 \implies 3\sqrt x - 2 = 0 \implies \sqrt x = \dfrac23 \implies \boxed{x = \dfrac49}$

and the derivative is undefined for

$\dfrac1{g'(x)} = 0 \implies 4x^{\frac34} = 0 \implies \boxed{x=0}$

8 0

2 years ago