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SIZIF [17.4K]
2 years ago
9

Describe how you know whether an equation will be true for all values of x or true for no values of x

Mathematics
1 answer:
love history [14]2 years ago
5 0

Answer:

<h2>brainiest me</h2>

Step-by-step explanation:

The value returned is TRUE if all of the values in x are TRUE (including if there are no values), and FALSE if at least one of the values in x is FALSE. Otherwise the value is NA (which can only occur if na.rm = FALSE and ... contains no FALSE values and at least one NA value).

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I think it’s the second one
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What is the answer to this question
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19

Step-by-step explanation:

when you multiply 19 by itself you get 361

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A table titled Number of Dogs Adopted has entries 3, 3, 4, 4, 4, 5, 5, 6, 6, 6, 7, 7, 7, 7, 8, 8, 8, 8, 8, 9, 9. The total is 13
saw5 [17]

Answer:

1) Mean = 6.28

2) Median = 7

3) Mode = 8

4) Range = 6

Step-by-step explanation:

We need to find Mean, Median, Mode and Range of data given in tables.

1) Mean

The formula used to calculate mean is: Mean=\frac{Sum\:of\:all\:data\:points}{Number\:of\:data\:points}

The data given is: 3, 3, 4, 4, 4, 5, 5, 6, 6, 6, 7, 7, 7, 7, 8, 8, 8, 8, 8, 9, 9

Sum of all data points = 132

Number of data points = 21

Finding mean:

Mean=\frac{Sum\:of\:all\:data\:points}{Number\:of\:data\:points}\\Mean=\frac{132}{21}\\Mean=6.28

So, Mean = 6.28

2) Median

The formula used to calculate median is: Median=\frac{n+1}{2}\:th\: term because we have n = odd

Number of data points n = 21

Putting values and finding the position of median term

Median=\frac{n+1}{2}\:th\: term\\Median=\frac{21+1}{2}\:th\: term\\Median=\frac{22}{2}\:th\: term\\Median=11\:th\:term

So, in the given data : 3, 3, 4, 4, 4, 5, 5, 6, 6, 6, 7, 7, 7, 7, 8, 8, 8, 8, 8, 9, 9

The 11 th term is 7

So, Median = 7

3) Mode

The mode is the most repetitive value of data set.

In the given data set: 3, 3, 4, 4, 4, 5, 5, 6, 6, 6, 7, 7, 7, 7, 8, 8, 8, 8, 8, 9, 9

The most repetitive value is 8

So, Mode = 8

4) Range

The range can be calculated using formula: Range=Maximum\:Value-Minimum\:Value

In the given data set: 3, 3, 4, 4, 4, 5, 5, 6, 6, 6, 7, 7, 7, 7, 8, 8, 8, 8, 8, 9, 9

Maximum value = 9

Minimum value = 3

So, the range is:

Range=Maximum\:Value-Minimum\:Value\\Range=9-3\\Range =6

So, Range = 6

3 0
3 years ago
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Help me match these pleasee and explain!
DiKsa [7]
3x=9 is C
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K=-9 Bc you move the variable to the left and then collect like terms and divide both sides
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