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Juliette [100K]
4 years ago
10

Which of the following is not an attribute of parallelograms?

Mathematics
2 answers:
nignag [31]4 years ago
7 0
On a basic parallelogram, opposite sides are parallel, diagonals bisect each other and, consecutive angles are supplementary. However on a parallelogram diagonals aren't congruent.

So the answer is D

Yakvenalex [24]4 years ago
4 0

Answer: is this right

Step-by-step explanation:

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The ratio fo boys to girls is 12:16
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Actually thats wrong bc my teacher did it with us but i really dont know the answer
Dvinal [7]

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???

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Which side lengths form a right triangle?
mr Goodwill [35]

B: 8,15,17

These lengths forms a

right angle triangle.

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3 years ago
WILL GIVE BRAINLIEST! SUPER CONFUSED!!!
kondor19780726 [428]

Answer:

For 1948 Men's :Interquartile range is 1.5, Median is 58.3

For 2012 Men's: Interquartile range is 0.315, Median is 47.86

You can infer that in 2012 the swimmers were better and it was more competitive as the interquartile range was lower and the median was also lower as well

Step-by-step explanation:

1948 Men's 100m

57.3, 57.8, 58.1, 58.3, 58.3, 59.3, 59.6,1:00.5

               ⬆                ⬆                 ⬆

         Low IQR      Median       High IQR

Low IQR is average of 57.8 and 58.1 = 57.95

High IQR  is average of 59.3 and 59.6 =  59.45

Median is average of 58.3 and 58.3 = 58.3

Interquartile range is High IQR- Low IQR

59.45 - 57.95=1.5

2012 Men's 100m

47.52, 47.53, 47.8, 47.84, 47.88, 47.92, 48.04, 48.44

                    ⬆                  ⬆                      ⬆

             Low IQR         Median          High IQR

Low IQR is average of 47.53 and 47.8 = 47.665

High IQR is average of 48.04 and 47.92 = 47.98

Median is average of 47.88 and 47.84 = 47.86

Interquartile range is High IQR-Low IQR

47.98-47.665=0.315

5 0
4 years ago
Which angles are vertical to DEA? Question is located in the attached file (image)​
ValentinkaMS [17]

Answer:

∠CEB

Step-by-step explanation:

The vertical angle is one that is directly <em>opposite</em> to the original angle. In this image of two intersecting lines, it looks like the angle ∠CEB is directly across from our angle ∠DEA. So, the angle ∠CEB is <em>vertical to</em> ∠DEA.

Hopefully that was helpful! :)

3 0
2 years ago
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