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Juliette [100K]
3 years ago
10

Which of the following is not an attribute of parallelograms?

Mathematics
2 answers:
nignag [31]3 years ago
7 0
On a basic parallelogram, opposite sides are parallel, diagonals bisect each other and, consecutive angles are supplementary. However on a parallelogram diagonals aren't congruent.

So the answer is D

Yakvenalex [24]3 years ago
4 0

Answer: is this right

Step-by-step explanation:

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A perpendicular bisector, CD is drawn through point C on AB. 
STALIN [3.7K]

<u>Answer</u>

B(18/5,0)


<u>Explanation</u>

First we find the coordinates of C;

C (x, y) = [(-3+7)/2, (2+6)/2]

           = (2, 4)

Find the equation of CD.

slope = (6-2)/(7--3)

         = 4/10  = 2/5

slope of CD = -5/2

-5/2 = (y - 4)/(x - 2)

-5/2(x - 2) = y - 4

(-5/2) x + 5 = y - 4

y = (-5/2)x + 9

For the x-intercept y = 0

∴ y = (-5/2)x + 9  

 0 = (-5/2)x + 9  

5/2 x = 9

x = 2/5 × 9

  = 18/5

x-intercept  = (18/5, 0)


3 0
3 years ago
Read 2 more answers
What is the slope of the line in the graph shown below?
ozzi
The slope is 3/2 or 1.5
6 0
2 years ago
Read 2 more answers
Find the area of rectangle with sides 2 5/6 and 4 4/7
g100num [7]
<h3><u>Given</u><u> </u><u>:</u></h3>

  • Length = \sf2\dfrac{5}{6} cm.
  • Breadth = \sf4\dfrac{4}{7} cm.

<h3><u>To</u><u> </u><u>Find</u><u> </u><u>:</u></h3>

The area of rectangle.

<h3><u>Solution</u><u> </u><u>:</u></h3>

Area of rectangle = Length × Breadth

\sf=2\dfrac{5}{6}\times4\dfrac{4}{7}

\sf=\dfrac{17}{6}\times\dfrac{25}{7}

\sf=\dfrac{17\times25}{6\times7}

\sf=\dfrac{425}{42}

<h3><u>Area</u><u> </u><u>of</u><u> </u><u>rectangle</u><u> </u><u>is</u><u> </u><u>4</u><u>2</u><u>5</u><u>/</u><u>4</u><u>2</u><u> </u><u>cm</u><u>²</u><u>.</u></h3>
4 0
3 years ago
Read 2 more answers
Who is the president of USA
den301095 [7]

Answer:

Donald Trump is the unfortunately current president of the united states.

if this is an actual question, you should have put it in the history category instead.

3 0
3 years ago
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X and y are positive integers. explain why incorrect to claim that
dedylja [7]

You can find counterexamples to disprove this claim. We have positive integers that are perfect square numbers; when we take the square root of those numbers, we get an integer.

For example, the square root of 1 is 1, which is an integer. So if y = 1, then the denominator becomes an integer and thus we get a quotient of two integers (since x is also defined to be an integer), the definition of a rational number.

Example: x = 2, y = 1 ends up with \frac{2}{\sqrt{1}} = \frac{2}{1} which is rational. This goes against the claim that x/\sqrt{y} is always irrational for positive integers x and y.

Any integer y that is a perfect square will work to disprove this claim, e.g. y = 1, y = 4, y= 9, y = 16. So it is not always irrational.

4 0
3 years ago
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