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Bingel [31]
3 years ago
11

I need help will mark brainlist

Mathematics
1 answer:
posledela3 years ago
7 0

Answer:

c

Step-by-step explanation:

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1
Papessa [141]

Answer:

d = 10/72

Step-by-step explanation:

c and d vary inversely

c = k/d

Where,

k = constant of proportionality

d = 2/9 when c = 5

c = k/d

5 = k ÷ 2/9

5 = k × 9/2

5 = 9k/2

Cross product

5*2 = 9k

10 = 9k

k = 10/9

c = k/d

c = 10/9 ÷ d

c = 10/9 × 1/d

c = 10/9d

find d when c = 8

c = 10/9d

8 = 10/9d

Cross product

8*9d = 10

72d = 10

d = 10/72

8 0
3 years ago
There is 6/8 of a cake leftover after a birthday party. How many 1/4 pieces can be made out of the leftover cake?
ikadub [295]

3/4 because if you make it smaller you would get that

4 0
4 years ago
Read 2 more answers
Leroy gave half of his crayons to a friend he then lost 2 he had 10 left how many crayons did he have to begin with
lakkis [162]

24 crayons he started with

6 0
3 years ago
Read 2 more answers
6. (08.02 MC)
MariettaO [177]

Answer:

The percentage change in volume between cylinder A and cylinder B is 50%

Step-by-step explanation:

The volume of a cylinder is given by the formula

V= πr^2h

For cylinder A, where r=7 and h= 5, π=22/7

V= π * 7^2 * 5

V= π * 49 * 5

V= 769.69 cubic inch

For cylinder B

V= 490π

V= 1539.3804 cubic inch

The percentage change in volume between cylinder A and cylinder B

=[ (VA- VB)/VB] *100

=( 1539.3804 - 769.69) / 1539.3804

= 0.5000 * 100

= 50%

8 0
3 years ago
Use multiplication or division of power series to find the first three nonzero terms in the Maclaurin series for the function. (
Mrrafil [7]

Answer:

So, the first three nonzero terms in the Maclaurin series are:

6, \, 27x^2, \, \frac{405x^4}{4}.

Step-by-step explanation:

From exercise we have the next function y = 6 sec(3x).

We know that Maclaurin series for the function sec x, have the following form:

\sec x=1+\frac{x^2}{2}+\frac{5x^4}{24}+...

So, for the given function y = 6 sec(3x), we get:

y = 6 \sec(3x)=6+27x^2+\frac{405x^4}{4}+...

So, the first three nonzero terms in the Maclaurin series are:

6, \, 27x^2, \, \frac{405x^4}{4}.

6 0
3 years ago
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