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polet [3.4K]
3 years ago
8

What is the slope of a line parallel to the line whose equation is x-3y=-27 Fully reduce your answer​

Mathematics
1 answer:
Alex17521 [72]3 years ago
3 0

Answer:

<h3>1/3</h3>

Step-by-step explanation:

Note that any line parallel to the given line will have the same slope as the line given.

Given the equation of the line expressed as x - 3y =-27

Rewrite in standard form y = mx+c where m is the slope

x - 3y =-27

-3y = -x -27

Multiply  through by -11

3y = x+27

Divide through by 3

y = 1/3 x + 9

Since the slope of the line is 1/3, hence the slope of a line parallel to the line is also 1/3

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Please show me how you got the answer. thanks in advance
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5 0
3 years ago
If isosceles triangle ABC has a 130° angle at vertex B, which statement must be true?
scZoUnD [109]

Answer:

Option B m<ZA+m<ZB = 155° is correct option.

Step-by-step explanation:

We know that sum of angles of triangle is equal to 180°

And Isosceles triangle, 2 angles are same

So, let  Angle 1 = x

Angle 2 = x

Angle 3 = 130°

Finding values of angle x

x+x+130=180

2x=180-130

2x=50

x=25

So, Angle 1 = 25 °

Angle 2 = 25°

As, angle B is greater than 90°, the sum of angles added must be greater than 90°

So, Option A, C and D can't be correct, as their sum is less than 90°

Option B m<ZA+m<ZB = 155° is correct option.

Verify:

m<ZA = 25° (as found earlier)

m<ZB = 130° (given)

So, m<ZA+m<ZB = 155°

25°+130° = 155°

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3 years ago
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vladimir1956 [14]
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Step-by-step explanation:

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Step-by-step explanation:

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