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rodikova [14]
3 years ago
11

Find the equation of this line. [?] x + [ ] y

Mathematics
2 answers:
Leona [35]3 years ago
8 0

Step-by-step explanation:

In a equation of a line

y=mx+c

Let's take two points from the graph (0,1) and (4,3)

Slope=m= (3-1/4-0)= 2/4=1/2

C= 1

y=½x+1

Neporo4naja [7]3 years ago
4 0

Answer:

y = ½x + 1

Step-by-step explanation:

the line pass through (x1,y1) as (-2,0) and (x2,y2) as (0,1) so the line equation can be determine by

\frac{y - y1}{y2 - y1}  =  \frac{x - x1}{x2 - x1}

(y-0)/(1-0) = (x-(-2))/(0-(-2))

y = (x+2)/2

y = ½x + 1

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Step-by-step explanation:

2.65 / 0.25 = 10.6 oz <===

4 0
4 years ago
Help me plz I only have 20 min!!
oksano4ka [1.4K]

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Step-by-step explanation:

7 0
3 years ago
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4 years ago
Use a coordinate grid to plot the points (—2, 3) and (4, 5) then plot two more points so that all four points form vértices of a
musickatia [10]

Answer:

The answer to your question is below

Step-by-step explanation:

See the picture below

Data

A (-2, 3)

B (4, 5)

I plotted the points C (4, 3) and D (-2, 5)

Distance

dAC = \sqrt{(4 + 2)^{2}+ (3-3)^{2}}

       = \sqrt{(6)^{2}}

      = 6

dBD = \sqrt{(4 + 2)^{2}+ (5 - 5)^{2}}

       = \sqrt{36}

      = 6

dAD = \sqrt{(-2 + 2)^{2} + (3 - 5)^{2}}

        = \sqrt{(-2)^{2}}

       = 2

dBC = \sqrt{(4 - 4)^{2} + (5 - 3)^{2}}

dBC = \sqrt{(2)^{2}}

dBC = 2

Total distance = dAC + dBD + dAD + dBC

Total distance = 6 + 6 + 2 + 2

                       = 16

I calculate the length of each side and then I sun them up.

4 0
3 years ago
I would really appreciate it if someone could answer this I will give a brainlist:)
Allushta [10]
97 I think

Steps:
72^2 + 65^2= c^2
5184 + 4225= c^2
9409= c^2
C= 97
8 0
3 years ago
Read 2 more answers
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