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rodikova [14]
3 years ago
11

Find the equation of this line. [?] x + [ ] y

Mathematics
2 answers:
Leona [35]3 years ago
8 0

Step-by-step explanation:

In a equation of a line

y=mx+c

Let's take two points from the graph (0,1) and (4,3)

Slope=m= (3-1/4-0)= 2/4=1/2

C= 1

y=½x+1

Neporo4naja [7]3 years ago
4 0

Answer:

y = ½x + 1

Step-by-step explanation:

the line pass through (x1,y1) as (-2,0) and (x2,y2) as (0,1) so the line equation can be determine by

\frac{y - y1}{y2 - y1}  =  \frac{x - x1}{x2 - x1}

(y-0)/(1-0) = (x-(-2))/(0-(-2))

y = (x+2)/2

y = ½x + 1

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ANEK [815]

Answer:

The correct option is;

∠A ≅ ∠X

Step-by-step explanation:

The given coordinates of the points of triangle ACB are;

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The given coordinates of the points of triangle XYZ are;

X(0, 8), Y(8, 8), Z(6, 2), therefore, we have

The length. l. of segment is given by the following formula;

l = \sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

For the length of the segment AC; (x₁, y₁) = (-4, 4), (x₂, y₂) = (-1, 3), l = √(10)

For the length of the segment AB; (x₁, y₁) = (-4, 4), (x₂, y₂) = (-4, 0), l = 4

For the length of the segment BC; (x₁, y₁) = (-4, 0), (x₂, y₂) = (-1, 3), l = 3·√2

For the length of the segment XY; (x₁, y₁) = (0, 8), (x₂, y₂) = (8, 8), l = 8

For the length of the segment XZ; (x₁, y₁) = (0, 8), (x₂, y₂) = (6, 2), l = 6·√2

For the length of the segment ZY; (x₁, y₁) = (6, 2), (x₂, y₂) = (8, 8), l = 2·√(10

Therefore;

XY ~ AB, XZ ~ BC, ZY ~ AC

Which gives;

∠A ≅ ∠X, ∠B ≅ ∠Y, ∠C ≅ ∠Z

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