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Luden [163]
3 years ago
7

Sylvester wants his hand to have a sum of -1. Click on three cards that Sylvester could choose. . -9 , 5 , -7, 1 , 4 , -2 , 3​

Mathematics
1 answer:
irina1246 [14]3 years ago
8 0
5,3 and -9 equal -1..
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PLEASEE HELLLLP!!!! THE PICTURE SHOWS THE MATH PROBLEM!
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4 x 3, 1/2 x 4, 1/2 x 3

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Can someone please help me
Mashutka [201]

\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the Concept of the Functions.

Let's first find the g(-1),

so we get as

3(-1)^2 +5(-1)-6

=> 3 -5-6

=> -8

now since g(-1) =-8

let's find f(g(-1)) that is f(-8)

f(-8) = 4(-8) + 14

=> f(g(-1)) = -32+14

=> f(g(-1)) = -18

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8 0
3 years ago
Problem 8-4 A computer time-sharing system receives teleport inquiries at an average rate of .1 per millisecond. Find the probab
Sphinxa [80]

Answer:  a) 0.9980, b) 0.0013, c) 0.0020, d) 0.00000026, e) 0.0318

Step-by-step explanation:

Problem 8-4 A computer time-sharing system receives teleport inquiries at an average rate of .1 per millisecond. Find the probabilities that the number of inquiries in a particular 50-millisecond stretch will be:

Since we have given that

\lambda=0.1\ per\ millisecond=5\ per\ 50\ millisecond=5

Using the poisson process, we get that

(a) less than or equal to 12

probability=  P(X\leq 12)=\sum _{k=0}^{12}\dfrac{e^{-5}(-5)^k}{k!}=0.9980

(b) equal to 13

probability= P(X=13)=\dfrac{e^{-5}(-5)^{13}}{13!}=0.0013

(c) greater than 12

probability= P(X>12)=\sum _{k=13}^{50}\dfrac{e^{-5}.(-5)^k}{k!}=0.0020

(d) equal to 20

probability= P(X=20)=\dfrac{e^{-5}(-5)^{20}}{20!}=0.00000026

(e) between 10 and 15, inclusively

probability=P(10\leq X\leq 15)=\sum _{k=10}^{15}\dfrac{e^{-5}(-5)^k}{k!}=0.0318

Hence, a) 0.9980, b) 0.0013, c) 0.0020, d) 0.00000026, e) 0.0318

6 0
3 years ago
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