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svet-max [94.6K]
2 years ago
6

Write the model of a 50 gram substance that decays at a rate of 3% yearly

Mathematics
1 answer:
Vadim26 [7]2 years ago
6 0

Answer:

A(t) = 50(0.97)^t

Step-by-step explanation:

3% = 0.03

1 - .03 = 0.97

A(t) = 50(1 - 0.03)^t

A(t) = 50(0.97)^t

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SOLUTIONS

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(A)

\begin{gathered} (f+g)(x)=(x^2+2x)+(1-x^2) \\ collect\text{ like terms} \\ x^2-x^2+2x+1 \\ (f+g)(x^)=2x+1 \end{gathered}

(B)

\begin{gathered} (f-g)(x)=(x^2+2x)-(1-x^2) \\ =x^2+2x-1+x^2 \\ =x^2+x^2+2x-1 \\ (f-g)(x)=2x^2+2x-1 \end{gathered}

(C)

\begin{gathered} fg(x)=(x^2+2x)(1-x^2) \\ =x^2-x^4+2x-2x^3 \\ fg(x)=-x^4-2x^3+x^2+2x \end{gathered}

(D)

\begin{gathered} \frac{f}{g}(x)=(x^2+2x)\div(1-x^2) \\ =\frac{x^2+2x}{1-x^2} \end{gathered}

5 0
1 year ago
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slavikrds [6]

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Step-by-step explanation:

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