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2 years ago

Solve for t. -18 = 6t A. t = -3 B. t = -1/3 C. t = 12 D. t = 24

Mathematics

2 answers:

dangina [55]2 years ago

6 0

Answer:

A) t = -3

Step-by-step explanation:

-18 = 6t

divide both sides of the equation by 6

-18/6 = 6t/6

-18/6 = t

-3 = t

vladimir1956 [14]2 years ago

3 0

Divide both sides of the equation by the same factor
−18=6t
6 6. that’s a fraction
t=-3

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Read 2 more answers

What is the value of x in the equation (StartFraction one-half EndFractionx + 12) = StartFraction one-half EndFraction(StartFrac

anastassius [24]

Answer:

$x =-24$

Step-by-step explanation:

Given

$(\frac{2}{3})(\frac{1}{2}x + 12) = (\frac{1}{2})(\frac{1}{3}x + 14) - 3$

Required

Solve for x

$(\frac{2}{3})(\frac{1}{2}x + 12) = (\frac{1}{2})(\frac{1}{3}x + 14) - 3$

Open all brackets

$\frac{2}{3}*\frac{1}{2}x + \frac{2}{3}*12 = \frac{1}{2}*\frac{1}{3}x + \frac{1}{2}*14 - 3$

$\frac{2 * 1}{3 *2}x + \frac{2 * 12}{3}= \frac{1 * 1}{2 * 3}x + \frac{1 * 14}{2} - 3$

$\frac{1}{3}x + \frac{24}{3}= \frac{1}{6}x + \frac{14}{2} - 3$

$\frac{1}{3}x +8= \frac{1}{6}x + 7 - 3$

Collect like terms

$\frac{1}{3}x - \frac{1}{6}x =7 - 3 -8$

$\frac{1}{3}x - \frac{1}{6}x =-4$

Solve fraction

$\frac{2-1}{6}x =-4$

$\frac{1}{6}x =-4$

Multiply both sides by 6

$6 * \frac{1}{6}x =-4 * 6$

$x =-4 * 6$

$x =-24$

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2 years ago