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Gemiola [76]
2 years ago
6

A bag contains seven tiles labeled B, C, D, E, F, G, and H. One tile will be randomly picked. What is the probability of picking

a vowel?
Write your answer as a fraction in simplest form
Mathematics
1 answer:
Licemer1 [7]2 years ago
7 0

Answer:

\sf \dfrac{1}{7}

Step-by-step explanation:

Given labeled tiles: B, C, D, E, F, G, H

Total number of tiles = 7

Vowels = A, E, I, O and U

⇒ Total number of vowel tiles in bag = 1

\sf Probability\:of\:an\:event\:occurring = \dfrac{Number\:of\:ways\:it\:can\:occur}{Total\:number\:of\:possible\:outcomes}

\implies \sf Probability\:of\:picking\:a\:vowel= \dfrac{Number\:of\:vowel\:tiles}{Total\:number\:of\:tiles}=\dfrac{1}{7}

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The arrivals of clients at a service firm in Santa Clara is a random variable from Poisson distribution with rate 2 arrivals per
ICE Princess25 [194]

Answer:

1.76% probability that in one hour more than 5 clients arrive

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

The arrivals of clients at a service firm in Santa Clara is a random variable from Poisson distribution with rate 2 arrivals per hour.

This means that \mu = 2

What is the probability that in one hour more than 5 clients arrive

Either 5 or less clients arrive, or more than 5 do. The sum of the probabilities of these events is decimal 1. So

P(X \leq 5) + P(X > 5) = 1

We want P(X > 5). So

P(X > 5) = 1 - P(X \leq 5)

In which

P(X \leq 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-2}*2^{0}}{(0)!} = 0.1353

P(X = 1) = \frac{e^{-2}*2^{1}}{(1)!} = 0.2707

P(X = 2) = \frac{e^{-2}*2^{2}}{(2)!} = 0.2707

P(X = 3) = \frac{e^{-2}*2^{3}}{(3)!} = 0.1804

P(X = 4) = \frac{e^{-2}*2^{4}}{(4)!} = 0.0902

P(X = 5) = \frac{e^{-2}*2^{5}}{(5)!} = 0.0361

P(X \leq 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.1353 + 0.2702 + 0.2702 + 0.1804 + 0.0902 + 0.0361 = 0.9824

P(X > 5) = 1 - P(X \leq 5) = 1 - 0.9824 = 0.0176

1.76% probability that in one hour more than 5 clients arrive

8 0
3 years ago
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a driver is below the surface of the water at - 15m. he dives down by 6m, then rises 4m where is he now​
nevsk [136]

Given:

A driver is below the surface of the water at - 15m. he dives down by 6m, then rises 4m.

To find:

The current location of the driver.

Solution:

In this problem, negative sign is used for downward direction or the distance below the surface of the water.

Initial location = -15 m

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Now, the current location is

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Therefore, the correct location of the driver is at -17 m it means her is 17 m  below the surface of the water.

6 0
3 years ago
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Lorico [155]
If Gail practises swimming for 1 and 1/4 hours a day, then in a week she'll do:

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In other words she'll practice 8 hours and 45 minutes a week (assuming that she's still practicing on weekends).
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Answer:

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Step-by-step explanation:

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Hope this helps!

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