Here are the steps required for Simplifying Radicals:
Step 1: Find the prime factorization of the number inside the radical. Start by dividing the number by the first prime number 2 and continue dividing by 2 until you get a decimal or remainder. Then divide by 3, 5, 7, etc. until the only numbers left are prime numbers. Also factor any variables inside the radical.
Step 2: Determine the index of the radical. The index tells you how many of a kind you need to put together to be able to move that number or variable from inside the radical to outside the radical. For example, if the index is 2 (a square root), then you need two of a kind to move from inside the radical to outside the radical. If the index is 3 (a cube root), then you need three of a kind to move from inside the radical to outside the radical.
Step 3: Move each group of numbers or variables from inside the radical to outside the radical. If there are nor enough numbers or variables to make a group of two, three, or whatever is needed, then leave those numbers or variables inside the radical. Notice that each group of numbers or variables gets written once when they move outside the radical because they are now one group.
Step 4: Simplify the expressions both inside and outside the radical by multiplying. Multiply all numbers and variables inside the radical together. Multiply all numbers and variables outside the radical together.
Shorter version:
Step 1: Find the prime factorization of the number inside the radical.
Step 2: Determine the index of the radical. In this case, the index is two because it is a square root, which means we need two of a kind.
Step 3: Move each group of numbers or variables from inside the radical to outside the radical. In this case, the pair of 2’s and 3’s moved outside the radical.
Step 4: Simplify the expressions both inside and outside the radical by multiplying.
I think your answers are 4 and 6
we are given that
f(x) is defined for all values of x except at x=c
Limit may or may not exist
case-1:
If there is hole at x=c , then limit exist
case-2:
If there is vertical asymptote at x=c , then limit does not exist
Examples:
case-1:
![\lim_{x \to c} \frac{x^2-cx}{(x-c)}](https://tex.z-dn.net/?f=%20%5Clim_%7Bx%20%5Cto%20c%7D%20%5Cfrac%7Bx%5E2-cx%7D%7B%28x-c%29%7D)
We can simplify it
![\lim_{x \to c} \frac{x(x-c)}{(x-c)}](https://tex.z-dn.net/?f=%20%5Clim_%7Bx%20%5Cto%20c%7D%20%5Cfrac%7Bx%28x-c%29%7D%7B%28x-c%29%7D)
![=\lim_{x \to c} x](https://tex.z-dn.net/?f=%20%3D%5Clim_%7Bx%20%5Cto%20c%7D%20x)
![=c](https://tex.z-dn.net/?f=%20%3Dc)
so, we can see that limit exist and it's value defined
case-2:
![\lim_{x \to c} \frac{1}{(x-c)}](https://tex.z-dn.net/?f=%20%5Clim_%7Bx%20%5Cto%20c%7D%20%5Cfrac%7B1%7D%7B%28x-c%29%7D)
Left limit is
![\lim_{x \to c-} \frac{1}{(x-c)}](https://tex.z-dn.net/?f=%20%5Clim_%7Bx%20%5Cto%20c-%7D%20%5Cfrac%7B1%7D%7B%28x-c%29%7D)
![=-\infty](https://tex.z-dn.net/?f=%20%3D-%5Cinfty)
Right Limit is
![\lim_{x \to c+} \frac{1}{(x-c)}](https://tex.z-dn.net/?f=%20%5Clim_%7Bx%20%5Cto%20c%2B%7D%20%5Cfrac%7B1%7D%7B%28x-c%29%7D)
![=+\infty](https://tex.z-dn.net/?f=%20%3D%2B%5Cinfty)
so, we can see that left limit is not equal to right limit
so, limit does not exist
Answer:55555
Step-by-step explanation:3 Points
Dawn's credit card has an APR of 15%, calculated on the previous monthly
balance, and a minimum payment of 2%, starting the month after the first
purchase. Her credit card record for the last 7 months is shown in the table
below.
End of
month
Previous
balance
50.00
51700.00
$1687 25
$1674 60
$1662 04
$1649.57
51637 20
New
charges
$1700 00
50.00
50 00
50.00
50.00
Payment
received
$0.00
$34 00
533 75
533 49
$3324
$32.99
$32.74
Finance
charges
50.00
521 25
$21 09
$20.93
$20.78
520 62
$20.46
Principal
paid
$0.00
$12.75
$1265
$12.56
$1247
$12.37
$1228
New
balance
$1700.00
$1687 25
51674 60
S1662 04
$1649 57
S1637 20
S1624 92
50.00
50.00
How much of the initial purchase has Dawn paid off over the 7 months?
Answer:
Step-by-step explanation: