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Lelu [443]
3 years ago
8

Select all statements below which are true for all invertible n×n matrices A and B

Mathematics
1 answer:
nirvana33 [79]3 years ago
7 0
The statements that are rue for <span>all invertible n×n matrices A and B are:
</span><span>(A+B)(A−B)=A^2−B^2
</span>and 
<span>(ABA^−1)^4=AB^4A^−1 
</span>From the above results we can conclude that the correct options among all the options that are given in the question are option "B" and option "E". I hope the answer helps you.
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Isn't the answer D? I will appreciate it if someone helps :)
Thepotemich [5.8K]
I think it is:) sorry if it is not
5 0
3 years ago
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Y=mx+b<br> Using ordered pair (900,1150)<br> Slope= 4/3<br><br> Solve for the y intercept
polet [3.4K]

Answer:

the y intercept is -50

Step-by-step explanation:

in y=mx+b, m is the slope and b is the y intercept. We are given the point (900,1150) and a slope of 4/3

we can susbstitute 4/3 into the equation.

y=4/3x+b

since the line will go through the point (900,1150), we can plug it into the equation.

1150=4/3(900)+b

1150=1200+b

-50=b

we are left with the y intercept (b) being -50. As a point, it's (0,-50)

Hope this helps!

8 0
3 years ago
Read 2 more answers
The 10th term in the sequence is 2560 what is the 11th term in the sequence
joja [24]

Full Question:

The 4th term of a g.p. is 40 and the 10th term in the sequence is 2560, what is the 11th term in the sequence ?

Answer:

the 11 the term is 5120

Step-by-step explanation:

Given

Geometry Progression

4th term = 40

10th term = 2560

Required

11 term.

The nth term of a geometric sequence is calculated as follows

Tₙ = arⁿ⁻¹

For the 4th term, n = 4 and Tₙ = 40

Substitute these in the given formula; this gives

40 = ar⁴⁻¹

40 = ar³. --;; equation 1

For the 10th term, n = 10 and Tₙ = 2560

Substitute these in the given formula; this gives

2560 = ar¹⁰⁻¹

2560 = ar⁹. --;; equation 2

Divide equation 2 by 1. This gives

2560/40 = ar⁹/ar³

64 = r⁹/r³

From laws of indices

64 = r⁹⁻³

64 = r⁶

Find 6th root of both sides

(64)^1/6 = r

r = (2⁶)^1/6

r = 2

Substitute r = 2 in equation 1

40 = ar³. Becomes

40 = a * 2³

40 = a * 8

40 = 8a

Divide both sides by 8

40/8 = 8a/8

5 = a

a = 5.

Now, the 11 term can be solved using Tₙ = arⁿ⁻¹ where n = 11

So,

Tₙ = arⁿ⁻¹ becomes

Tₙ = 5 * 2¹¹⁻¹

Tₙ = 5 * 2¹¹⁻¹

Tₙ = 5 * 2¹⁰

Tₙ = 5 * 1024

Tₙ = 5120.

Henxe, the 11 the term is 5120

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3 years ago
kelly has 47 model cars. Jamal has 58 model cars. Yesterday , jamal traded 8 model cars to kelly for 14 of her cars. How many ca
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Answer:

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3 years ago
Write an equation that expresses the following relationship.
ahrayia [7]

Given:

u varies directly with the square of p and inversely with d.

To find:

The equation for the given situation.

Solution:

If y is directly proportional to x, then

y\propto x

If y is inversely proportional to x, then

y\propto \dfrac{1}{x}

It is given that u varies directly with the square of p and inversely with d. So,

u\propto \dfrac{p^2}{d}

It can be written as:

u=k\dfrac{p^2}{d}

Where, k is the constant of proportionality.

Therefore, the required equation is u=\dfrac{kp^2}{d}.

6 0
3 years ago
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