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3 years ago

Simplify -1/2+3-4x+5+3/2x

Mathematics

1 answer:

Oxana [17]3 years ago

7 0

-5/2x+15/2

That is the simplified version. Let me know if you need any work...

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Find the equation of a circle whose center is at (-3, 7) and radius is 9 units.

timurjin [86]

Answer:

(x + 3)² + (y - 7)² = 81

Step-by-step explanation:

the equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k ) are the coordinates of the centre and r the radius

here (h, k ) = (- 3, 7 ) and r = 9 , then

(x - (- 3) )² + (y - 7)² = 9² , that is

(x + 3)² + (y - 7)² = 81

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2 years ago

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A triangle has sides 12cm, 9cm and 15cm. Is the triangle right-angled? Justify your answer

marusya05 [52]

Answer:

yes

Step-by-step explanation:

Yes this triangle is right angled and can be justified using the Pythagorean theorem. The theorem states that: $a^{2} +b^{2} = c^{2}$ . Substitute using the given values:

(9^2)+(12^2)=15^2

81 + 144 = 255

255 = 255.

It satisfies the theorem therefore it is a right angle triangle.

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3 years ago

Write the expression as a single natural logarithm.3In3+3Inc

k0ka [10]

Answer:

$ln(27c^3)$

Step-by-step explanation:

Given: $3ln(3)+3ln(c)$

If there is a coefficient in front of a $log$ or $ln$ , that means it becomes an exponent.

$ln(3^3)+ln(c^3)$

Simplify the exponent.

$ln(27)+ln(c^3)$

When there is addition between two logarithms or natural logarithms, it means they multiply together.

$ln(27c^3)$

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4 years ago

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The roots of Billy's plant grew to 3 inches beneath the Earth’s surface. Graph all the possible depths the roots can continue to

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Answer:

Step-by-step explanation:relax and claculate in ur mine

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3 years ago

student randomly receive 1 of 4 versions(A, B, C, D) of a math test. What is the probability that at least 3 of the 5 student te

alexdok [17]

Answer:

1.2%

Step-by-step explanation:

We are given that the students receive different versions of the math namely A, B, C and D.

So, the probability that a student receives version A = $\frac{1}{4}$ .

Thus, the probability that the student does not receive version A = $1-\frac{1}{4}$ = $\frac{3}{4}$ .

So, the possibilities that at-least 3 out of 5 students receive version A are,

1) 3 receives version A and 2 does not receive version A

2) 4 receives version A and 1 does not receive version A

3) All 5 students receive version A

Then the probability that at-least 3 out of 5 students receive version A is given by,

$\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}$