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kifflom [539]
3 years ago
5

29. What is the noble gas configuration for tellurium?

Chemistry
1 answer:
Whitepunk [10]3 years ago
5 0

Answer:

[Kr] 4d10 5s2 5p4 is the electronic configuration for tellurium.

Electrons per shell: 2,8,18,18,6

Atomic number: 52

Symbol: Te

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There are two binary compounds of mercury and oxygen. heating either of them results in the decomposition of the compound, with
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\text{Hg} \text{O} and \text{Hg}_{2} \text{O}.

Assuming complete decomposition of both samples,

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First compound:

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n = m/M; 0.6498 \; g of the first compound would contain

  • n(\text{O atoms}) = 0.048 \; g  / 16 \; g \cdot mol^{-1}= 0.003 \; mol
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Oxygen and mercury atoms seemingly exist in the first compound at a 1:1 ratio; thus the empirical formula for this compound would be \text{Hg} \text{O} where the subscript "1" is omitted.

Similarly, for the second compound

  • m(\text{O}) = m(\text{loss}) = 0.016 \; g
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n = m/M; 0.4172 \; g of the first compound would contain

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n(\text{Hg}) : n(\text{O}) \approx  2:1 and therefore the empirical formula

\text{Hg}_{2} \text{O}.

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