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3 years ago

The synthesis of nitrogen trihydride from nitrogen gas and hydrogen gas is shown by which balanced chemical equation?

2 answers:

7 0

The correct answer is: [B]:
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" N₂ (g) + 3 H₂ (g) → 2 NH₃ <span>(g) " .
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Note of interest:
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This particular reaction is known as the "</span>Haber process" .
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DENIUS [597]3 years ago

6 0

Hello!

The synthesis of nitrogen trihydride from nitrogen gas and hydrogen gas is shown by the following balanced chemical equation:

B) N₂(g) + 3H₂(g) → 2NH₃(g)

The question is saying that the reactants are nitrogen gas (N₂) and hydrogen gas (H₂). This rules out options C and D, because they do not have those reactants.

The remaining options (A and B) show the formation of Nitrogen Trihydride (NH₃, also called Ammonia), from Nitrogen gas and Hydrogen gas, but option A is not balanced (the number of each atom on both sides of the equation is not the same).

So, the correct option is B, it shows the balanced reaction accurately. This reaction is also known as the "Haber-Bosch Process", invented by Fritz Haber and Carl Bosch in the early 20th century.

Have a nice day!

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I wanted known how many of the reaction below is energy released

Tema [17]

Answer:

Explanation:

In two reactions energy is released.

1) C₆H₁₂O₆ + 6O₂ → 6H₂O + 6CO₂ + heat

It is cellular respiration reaction.It involves the breakdown of glucose molecule in the presence of oxygen to yield large amount of energy. Water and carbon dioxide are also produced as a byproduct.

Glucose + oxygen → carbon dioxide + water + 38ATP

2) 2H₂ + O₂ → 2H₂O ΔH = -486 kj/mol

The given reaction is formation of water. In this reaction oxygen and hydrogen react to form water and 486 kj/mol is also released.

The reaction in which heat is released is called exothermic reaction.

Exothermic reaction:

The type of reactions in which energy is released are called exothermic reactions.

In this type of reaction energy needed to break the bonds are less than the energy released during the bond formation.

For example:

Chemical equation:

C + O₂ → CO₂

ΔH = -393 Kj/mol

it can be written as,

C + O₂ → CO₂ + 393 Kj/mol

Endothermic reactions:

The type of reactions in which energy is absorbed are called endothermic reactions.

In this type of reaction energy needed to break the bond are higher than the energy released during bond formation.

For example:

C + H₂O → CO + H₂

ΔH = +131 kj/mol

it can be written as,

C + H₂O + 131 kj/mol → CO + H₂

5 0

3 years ago

A 0.5438 g of a C.H.O. compound was combusted in air to make 1.039 g of CO2 and 0.6369 g H20. What is the empirical formula? Bal

goblinko [34]

Answer:

C₃H₅O₂

4C₃H₅O₂ + 13O₂ → 12CO₂ + 10H₂O

Explanation:

The reaction can be expressed as:

CₓHₓOₓ + nO₂ → CO₂ + H₂O

Under the assumption that there was a total combustion, all of the carbon in the reactant was combusted into CO₂, so <u>the mass of C contained in the C.H.O. compound is the same mass of C contained in 1.039 g of CO₂</u>:

$1.039gCO_{2}*\frac{1molCO_{2}}{44gCO_{2}} *\frac{1molC}{1molCO_{2}} *\frac{12gC}{1molC} =0.2834gC$

All of the hydrogens atoms in the compound ended up becoming H₂O, so <u>the mass of H contained in the C.H.O. compound is the same mass of H contained in 0.6369 g of H₂O</u>:

$0.6369g*\frac{1molH_{2}O}{18gH_{2}O} *\frac{1molH}{1molH_{2}O} *\frac{1gH}{1molH} =0.0354gH$

Because the compound is composed only by C, H and O, <u>the mass of O in the compound can be calculated by substraction</u>:

0.5438 g Compound - 0.2834 g C - 0.0354 g H = 0.2250 g O

In order to determine the empirical formula, we calculate the moles of each component:

mol C = 0.2834 g C ÷ 12 g/mol = 0.0236 mol C

mol H = 0.0354 g H ÷ 1 g/mol = 0.0354 mol H

mol O = 0.2250 g O ÷ 16 g/mol = 0.0141 mol O

Then we divide those values by the lowest one:

0.0236 mol C ÷ 0.0141 = 1.67

0.0354 mol H ÷ 0.0141 = 2.51

0.0141 mol O ÷ 0.0141 = 1

If we multiply those values by 2, we're left with the empirical formula C₃H₅O₂.

The reaction is:

4C₃H₅O₂ + 13O₂ → 12CO₂ + 10H₂O

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<em />

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2 years ago

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mina [271]

Answer:

think it helps you

<h2>Explanation:</h2>

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3 years ago