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3 years ago

The synthesis of nitrogen trihydride from nitrogen gas and hydrogen gas is shown by which balanced chemical equation?

2 answers:

7 0

The correct answer is: [B]:
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" N₂ (g) + 3 H₂ (g) → 2 NH₃ <span>(g) " .
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Note of interest:
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This particular reaction is known as the "</span>Haber process" .
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DENIUS [597]3 years ago

6 0

Hello!

The synthesis of nitrogen trihydride from nitrogen gas and hydrogen gas is shown by the following balanced chemical equation:

B) N₂(g) + 3H₂(g) → 2NH₃(g)

The question is saying that the reactants are nitrogen gas (N₂) and hydrogen gas (H₂). This rules out options C and D, because they do not have those reactants.

The remaining options (A and B) show the formation of Nitrogen Trihydride (NH₃, also called Ammonia), from Nitrogen gas and Hydrogen gas, but option A is not balanced (the number of each atom on both sides of the equation is not the same).

So, the correct option is B, it shows the balanced reaction accurately. This reaction is also known as the "Haber-Bosch Process", invented by Fritz Haber and Carl Bosch in the early 20th century.

Have a nice day!

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Given

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Answer:

Following are the responses to this question:

Explanation:

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2 years ago

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Answer:

For 1 antacid tablet (in ballon1) we get .0173 moles of CO2

for 2 tablets (in balloon 2) we get: 2*0,0173= 0.0346 moles of CO2

For 3 tablets (in balloon 3) we get 3* 0.0173 = 0.0519 moles of CO2

Explanation:

The complete question:

Calculate the theoretical value for the number of moles of CO2 that should have been produced in each balloon assuming that 1.45 g of NaHCO3 is present in an antacid tablet. Use stoichiometry (a mole ratio conversion must be present) to find your answers (there should be three: one answer for each balloon).

Balloon 1 had 1 antacid tab

Baloon 2 had 2

Balloon 3 had 3

Step 1: Data given

1.45 g of NaHCO3 is present in an antacid tablet

Molar mass of NaHCO3 = 84.00 g/mol

Step 2: The balanced equation

NaHCO3 + H2O → NaOH + H2O + CO2

Step 3: Calculate moles of NaHCO3

Moles NaHCO3 = mass NaHCO3 / molar mass NaHCO3

1.45g / 84.0 g/mol = .0173 moles

Step 4: Calculate moles CO2

For 1 mol NaHCO3 we need 1 mol H2O to produce 1 mol NaOH 1 mol H2O and 1 mol CO2

For 0.0173 moles NaHCO3 we'll get 0.0173 moles CO2

so for 1 antacid tablet we get .0173 moles of CO2

for 2 tablets we get: 2*0,0173 = 0.0346 moles of CO2

For 3 tablets we get 3* 0.0173 = 0.0519 moles of CO2

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3 years ago

Read 2 more answers