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4 years ago

The synthesis of nitrogen trihydride from nitrogen gas and hydrogen gas is shown by which balanced chemical equation?

2 answers:

7 0

The correct answer is: [B]:
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" N₂ (g) + 3 H₂ (g) → 2 NH₃ <span>(g) " .
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Note of interest:
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This particular reaction is known as the "</span>Haber process" .
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DENIUS [597]4 years ago

6 0

Hello!

The synthesis of nitrogen trihydride from nitrogen gas and hydrogen gas is shown by the following balanced chemical equation:

B) N₂(g) + 3H₂(g) → 2NH₃(g)

The question is saying that the reactants are nitrogen gas (N₂) and hydrogen gas (H₂). This rules out options C and D, because they do not have those reactants.

The remaining options (A and B) show the formation of Nitrogen Trihydride (NH₃, also called Ammonia), from Nitrogen gas and Hydrogen gas, but option A is not balanced (the number of each atom on both sides of the equation is not the same).

So, the correct option is B, it shows the balanced reaction accurately. This reaction is also known as the "Haber-Bosch Process", invented by Fritz Haber and Carl Bosch in the early 20th century.

Have a nice day!

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3 years ago

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A sample compound with a molar mass of 34.00g/mol is found to consist of 0.44g H and 6.92g O. Calculate both empirical and molec

balu736 [363]

Answer:

E.F= OH

M.F= $O_{2} H_{2}$

Explanation:

Empirical Formula

Step 1: Calculate mols of each element

0.44gH(1 mol H/ 1.008g H)= 0.4365 mol H

*note leave extra sig figs for calculations

6.92gO(1 mol O/ 16 g O)=0.4325 mol O

Step 2: Identify which is the smallest mol

*in this case 0.4365 mol H> 0.4325 mol O so we will use 0.4325 mol O

Step 3: Divide above calculations by the smallest mol

0.4325 mol O/0.4325= 1

0.4365 mol H/0.4325= 1.009 *rounds to 1

Step 4: use calculations as subscripts

Oxygen = 1 so the subscript will 1 (O)

Hydrogen = 1 so the subscript will 1 (H)

making E.F= OH

Molecular Formula:

Step 1: identify molecular mass and mass from the E.F

the molecular mass is given 34.00g/mol

the mass of the E.F is

(oxygen mass from periodic table)+(hydrogen mass from periodic table)

16+1.008= 17.008

Step 2:Divide the molecular mass by the mass given by the emipirical formula.

$\frac{34.00}{17.008}= 1.999$ round to 2

Step 3:Multiply the empirical formula (the subscripts) by this number to get the molecular formula. ANSWER: M.F=2(OH)- $O_{2} H_{2}$

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