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anygoal [31]
3 years ago
11

Positive ions from a base and negative ions from an acid form a_____ .

Chemistry
2 answers:
lara31 [8.8K]3 years ago
5 0
They will form a Salt
Anna35 [415]3 years ago
4 0

Explanation:

Bases are the species which contain OH^{-} ions whereas acids are the species which contain H^{+} ions. When positive ions from a base reacts with negative ions of an acid then it results in the formation of salt.

For example, when base NaOH reacts with hydrochloric acid then it results in the formation of sodium chloride and water.

The reaction is as follows.

        NaOH + HCl \rightarrow NaCl + H_{2}O

Thus, we can conclude that positive ions from a base and negative ions from an acid form a salt.

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How many moles of magnesium are needed to react with 3.0 mol of O2?
labwork [276]

Answer:

2 moles

Explanation:

6 0
2 years ago
What does 2n² ?denote explain it with the help of two example<br>​
Lana71 [14]

Answer:

2n² means 2 × n × n . the power on the n represent the no. of time it is multiplied.

for ex 3x² = 3 × x × x

4x⁴ = 4 × X× X × X× X

8 0
3 years ago
What do cubic measurements, live cm3, mesure?"<br> O length<br> volume
anygoal [31]
The answer is volume.
6 0
2 years ago
What is the minimum cation-to-anion radius ratio (rC/rA) for an octahedral interstitial lattice site?
mash [69]

Answer:

0. 414

Explanation:

Octahedral interstitial lattice sites.

Octahedral interstitial lattice sites are in a plane parallel to the base plane between two compact planes and project to the center of an elementary triangle of the base plane.

The octahedral sites are located halfway between the two planes. They are vertical to the locations of the spheres of a possible plane. There are, therefore, as many octahedral sites as there are atoms in a compact network.

The Octahedral interstitial void ratio range is 0.414 to 0.732. Thus, the minimum cation-to-anion radius ratio for an octahedral interstitial lattice site is 0. 414.

3 0
2 years ago
For the chemical reaction
polet [3.4K]

Answer:

806.3g

Explanation:

Given parameters:

 Number of moles of silver nitrate  = 4.85mol

Unknown:

Mass of silver chromate = ?

Solution:

         2AgNO₃ + Na₂CrO₄  →  Ag₂CrO₄ + 2NaNO₃

To solve this problem, we work from the known to the unknown;

  • The known specie here is  AgNO₃ ;

   From the balanced chemical equation;

          2 moles of AgNO₃  will produce 1 mole of Ag₂CrO₄

          4.85 moles of AgNO₃  will produce \frac{4.85}{2}   = 2.43moles of Ag₂CrO₄

  • Mass of silver chromate produced;

        mass = number of moles x molar mass

   Molar mass of  Ag₂CrO₄

    Atomic mass of Ag = 107.9g/mol

                                 Cr  = 52g/mol

                                  O  = 16g/mol

  Input the parameters and solve;

     Molar mass  = 2(107.9) + 52 + 4(16) = 331.8g/mol

  So,

        Mass of Ag₂CrO₄ = 2.43 x 331.8 = 806.3g

     

8 0
2 years ago
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