The Empirical formula of compound is C₁H₂O₁. The Molecular Formula of the compound is 4 (C₁H₂O₁).
<h3>What is Empirical Formula ?</h3>
Empirical formula is the simplest whole number ratio of atoms present in given compound.
Element % Atomic mass Relative no. of atoms Simplest whole ratio
C 40.6 12 
= 3.3 
H 5.1 1 
= 5.1 
O 54.2 16 
= 3.3
The Empirical formula of compound is C₁H₂O₁ or CH₂O
<h3>How to find the Molecular formula of compound ?</h3>
Molecular formula = Empirical formula × n
= 4
Molecular formula = n × Empirical formula
= 4 (C₁H₂O₁)
Thus from the above conclusion we can say that The Empirical formula of compound is C₁H₂O₁. The Molecular Formula of the compound is 4 (C₁H₂O₁).
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Answer:
Answer is: Keq = [CO₂].
Explanation:
Balanced chemical reaction: CaCO3(s) ⇄ CaO(s) + CO₂(g).
The equilibrium constant (Keq) is a ratio of the concentration of the products to the concentration of the reactants.
Pure liquids (shown in chemical reactions by appending (l) to the chemical formula) and solids (shown in chemical equations by appending (s) to the chemical formula) not go in to he equilibrium constant expression, only gas state (shown in chemical reactions by appending (g) to the chemical formula) reactants and products go in to the equilibrium constant expression
Answer:
Because burning a non-renewable resource that is not good for the atmosphere, will always cause some kind of chemical reaction to happen.
Examples of these reactions are...
- Acid rain, a very dangerous disaster.
- Global warming.
- Carbon increases.
Answer:
The health hazard warning label on Sweet ‘N Low packets has been removed, however, dangers may still lurk. According to the FDA, saccharin has been linked to bladder cancer in laboratory animals which prompted them to require warning labels on products containing this artificial sweetener in 1977.
Explanation:
Answer:
No, I can not identify the contents of each bottle using solubility and polarity (with H2O) information
Explanation:
While it is true that polar substances dissolve in water and nonpolar substances do not dissolve in water, the task here is to specifically identify the contents of each of the bottles.
Solubility in water can not tell us exactly what liquid is which substance. For instance, trans-1,2-dichloroethylene, cis-1,2-dichloroethylene and cyclooctane are all insoluble in water. The fact that they do not dissolve in water does not tell us which liquid is which compound.
Even though acetic acid is miscible with water, it is not a conclusive prove that the liquid is acetic acid since other polar organic compounds are also miscible in water.
It is only by determining the boiling point of each substance that I can conclusively identify the contents of each bottle since boiling point is an intrinsic property of substances.
