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3 years ago

Please help me i have no clue what to do

Mathematics

2 answers:

kenny6666 [7]3 years ago

6 0

Answer:

Your suppose to plot the numbers above by the x and y axis

Step-by-step explanation:

ludmilkaskok [199]3 years ago

6 0

Answer & Step-by-step explanation:

The vertical line test is used to determine if a given relation is a function.

How it works:

You can use anything that has a straight edge, usually a pencil. Hold it up to the graph at multiple points vertically.

Now, if the pencil crosses over two points, the relation is not a function. If you hold the pencil to the graph and it doesn't cross over two points, then the relation is a function.

If you hold a pencil to the graph vertically at each given point, the pencil does not cross over two points. Therefore, the relation is a function.

:Done

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On an airplane flight, Steve watch the display that showed the number of minutes since the flight to cough and the number of mil

FromTheMoon [43]

Answer:

3386 miles was her destination......

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3 years ago

Name the following triangles please....

Naily [24]

Answer:

Equilateral Triangle
Right angle triangle
Isosceles triangle

Step-by-step explanation:

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8 0

3 years ago

Read 2 more answers

The thickness of a ﬂange on an aircraft component is uniformly distributed between 0.95 and 1.05 millimeters. Determine the foll

Mrrafil [7]

Answer

given,

thickness of a ﬂange on an aircraft component is uniformly distributed between 0.95 and 1.05 millimeters.

X = U[0.95,1.05] 0.95≤ x ≤ 1.05

the cumulative distribution function of flange

F(x) = P{X≤ x}= $\dfrac{x-0.95}{1.05-0.95}$

= $\dfrac{x-0.95}{0.1}$

b) P(X>1.02)= 1 - P(X≤1.02)

= $1- \dfrac{1.02-0.95}{0.1}$

= 0.3

c) The thickness greater than 0.96 exceeded by 90% of the ﬂanges.

d) mean = $\dfrac{0.95+1.05}{2}$

= 1

variance = $\dfrac{(1.05-0.95)^2}{12}$

= 0.000833

4 0

4 years ago

The time, t, required to travel a fixed distance varies inversely as the

Lemur [1.5K]

You must travel at 42 mph for 4 hours

Solution:

Time varies inversely as rate of motion

Let "t" be the time required

Let "r" be the rate of motion

Then, we get

$t \propto \frac{1}{r}\\\\t = k \times \frac{1}{r}\\\\t = \frac{k}{r} -------- eqn 1$

Where, "k" is the constant of proportionality

You travel 3 hours at a rate of 56 mph

Substitute t = 3 and r = 56 in eqn 1

$3 = \frac{k}{56}\\\\k = 3 \times 56\\\\k = 168$

Find the rate you must travel for 4 hours

r = ? and t = 4

Substitute t = 4 and k = 168 in eqn 1

$4 = \frac{168}{r}\\\\r = \frac{168}{4}\\\\r = 42$

Thus you must travel at 42 mph for 4 hours

4 0

4 years ago

Michael breeds chickens and ducks. Last month, he sold 50 chickens and 30 ducks for $550. This month, he sold 44 chickens and 36

Radda [10]

Answer:

a chicken cost $4

a duck cost $11.66

Step-by-step explanation:

Let the cost of one chicken be x

then cost of 50 chicken = 50x

cost of one duck be y

cost of 30 ducks = 30y

It is given that 50 chickens and 30 ducks cost $550

thus

50x+30y = 550

dividing LHS and RHS by 10 we have

50x/10+30y/10 = 550/10

=>5x+3y = 55 ____________________(1)

_________________________________

for this month we have calculation as given below

cost of 44 chicken = 44x

cost of 36 ducks = 36y

It is given that 44 chickens and 36 ducks cost $532

thus

44x+36y = 532

dividing LHS and RHS by 4 we have

44x/4+36y/4 = 532/4

=>11x+9y = 133 ______________2

__________________________________

we have equation

5x+3y = 55 ____________________(1)

11x+9y = 133 ______________2

multiplying equation 1 by 3 on LHS and RHS we have.

(note: multiplication with3 is done to transform 3y into 9y

so that y can be removed from equation)

5x*3+3y*3 = 55*3

=> 15x+9y = 165 ___(3)

subtracting equation 3 from equation 1 we have

15x+9y = 165

-(11x+9y )= 133

15x +9y -11x -9y = 165 - 133

=> 4x = 32

=> x = 32/4 = 4

5x+3y = 55

=>5*4 +3y = 55

=>20+ 3y = 55

=>3y = 55-20 = 35

=>y = 35/3 =11.66

Thus,a chicken cost $4

a duck cost $11.66

5 0

3 years ago