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N76 [4]
4 years ago
15

Plese help im in 2nd grade and this is really hard all the kids in my class know it but me​

Mathematics
2 answers:
Marina86 [1]4 years ago
6 0

Answer:

This isn't in second gradee- x-x

Step-by-step explanation:

Colt1911 [192]4 years ago
4 0

Answer: For x such that 0<x<(pie/2), the expression:

[square-root(1-cos^2(x)]/sinx + [square-root(1-sin^2(x)]/cos(x)

is equivalent to,

F. 0

G. 1

H. 2

J. -tan(x)

K. sin2x

The answer is H.

Step-by-step explanation:

You might be interested in
Fine the value for X that makes
Nesterboy [21]

Answer:

60

Step-by-step explanation:

x and 2x are linear pair angles.

Sum of linear pair angles is 180,

x + 2x = 180

3x = 180

x = 180 / 3

x = 60

Therefore,

the value of x is 60.

6 0
3 years ago
Read 2 more answers
Area of the bounded curves y=x^2, y=√(7+x)
N76 [4]

Answer:

\displaystyle \int\limits^{1.718}_{-1.529} {\sqrt{7 + x} - x^2} \, dx = 5.74773

General Formulas and Concepts:

<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Derivative Property [Addition/Subtraction]:                                                         \displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]  

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Integration

  • Integrals

Integration Rule [Reverse Power Rule]:                                                               \displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C

Integration Rule [Fundamental Theorem of Calculus 1]:                                     \displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)

Integration Property [Addition/Subtraction]:                                                       \displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx

U-Substitution

Area of a Region Formula:                                                                                     \displaystyle A = \int\limits^b_a {[f(x) - g(x)]} \, dx

Step-by-step explanation:

<u>Step 1: Define</u>

\displaystyle \left \{ {{y = x^2} \atop {y = \sqrt{7 + x}}} \right.

<u>Step 2: Identify</u>

<em>Graph the systems of equations - see attachment.</em>

Top Function:  \displaystyle y = \sqrt{7 + x}

Bottom Function:  \displaystyle y = x^2

Bounds of Integration: [-1.529, 1.718]

<u>Step 3: Integrate Pt. 1</u>

  1. Substitute in variables [Area of a Region Formula]:                                   \displaystyle \int\limits^{1.718}_{-1.529} {\sqrt{7 + x} - x^2} \, dx
  2. [Integral] Rewrite [Integration Property - Addition/Subtraction]:               \displaystyle \int\limits^{1.718}_{-1.529} {\sqrt{7 + x} - x^2} \, dx= \int\limits^{1.718}_{-1.529} {\sqrt{7 + x}} \, dx - \int\limits^{1.718}_{-1.529} {x^2} \, dx
  3. [Right Integral] Integration Rule [Reverse Power Rule]:                             \displaystyle \int\limits^{1.718}_{-1.529} {\sqrt{7 + x} - x^2} \, dx= \int\limits^{1.718}_{-1.529} {\sqrt{7 + x}} \, dx - \frac{x^3}{3} \bigg| \limits^{1.718}_{-1.529}
  4. Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]:           \displaystyle \int\limits^{1.718}_{-1.529} {\sqrt{7 + x} - x^2} \, dx= \int\limits^{1.718}_{-1.529} {\sqrt{7 + x}} \, dx - 2.88176

<u>Step 4: Integrate Pt. 2</u>

<em>Identify variables for u-substitution.</em>

  1. Set <em>u</em>:                                                                                                             \displaystyle u = 7 + x
  2. [<em>u</em>] Basic Power Rule [Derivative Rule - Addition/Subtraction]:                 \displaystyle du = dx
  3. [Limits] Switch:                                                                                               \displaystyle \left \{ {{x = 1.718 ,\ u = 7 + 1.718 = 8.718} \atop {x = -1.529 ,\ u = 7 - 1.529 = 5.471}} \right.

<u>Step 5: Integrate Pt. 3</u>

  1. [Integral] U-Substitution:                                                                               \displaystyle \int\limits^{1.718}_{-1.529} {\sqrt{7 + x} - x^2} \, dx= \int\limits^{8.718}_{5.471} {\sqrt{u}} \, du - 2.88176
  2. [Integral] Integration Rule [Reverse Power Rule]:                                       \displaystyle \int\limits^{1.718}_{-1.529} {\sqrt{7 + x} - x^2} \, dx = \frac{2x^\Big{\frac{3}{2}}}{3} \bigg| \limits^{8.718}_{5.471} - 2.88176
  3. Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]:           \displaystyle \int\limits^{1.718}_{-1.529} {\sqrt{7 + x} - x^2} \, dx = 8.62949 - 2.88176
  4. Simplify:                                                                                                         \displaystyle \int\limits^{1.718}_{-1.529} {\sqrt{7 + x} - x^2} \, dx = 5.74773

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

5 0
3 years ago
For x &gt; 3, values of the function f(x) = –(x – 3)^2(x + 2) are negative. On this same interval, which statement correctly des
Leokris [45]
The addictive inverse is positive while the multiplicative inverse is negative
4 0
4 years ago
Read 2 more answers
I am not able to solve this problem​
Soloha48 [4]

First, 0.0004853 is < 1, so we need to multiply the number by 10 to a negative power if it's greater than 1 (if that makes sense i cant describe it better)

So, b and c is incorrect.

10 to the power of negative 4 = 0.0001, and 4.853 x 0.0001 = 0.0004853 (true), so answer is a

8 0
2 years ago
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nikki grows 12 tomato plants. she measures their heights to the nearest centimetre, and writes them down. Complete the frequency
sdas [7]

Answer:

Nikki grows 20 tomato plants and she measures their heights.

We want to complete the frequency table.

All we have to do is count the number of values that fall between each range.

The values are:

5  10  12  16  14

17  20  15  10  7

13  11  6  18  15

6  12  17  8  12

  Height              Frequency

-> 5 ≤ h < 10             5

10 ≤ h < 15                8

15 ≤ h < 20               6

20 ≤ h < 25               1

5 0
4 years ago
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