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4 years ago

Plese help im in 2nd grade and this is really hard all the kids in my class know it but me

Mathematics

2 answers:

Marina86 [1]4 years ago

6 0

Answer:

This isn't in second gradee- x-x

Step-by-step explanation:

Colt1911 [192]4 years ago

4 0

Answer: For x such that 0<x<(pie/2), the expression:

[square-root(1-cos^2(x)]/sinx + [square-root(1-sin^2(x)]/cos(x)

is equivalent to,

F. 0

G. 1

H. 2

J. -tan(x)

K. sin2x

The answer is H.

Step-by-step explanation:

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Fine the value for X that makes

Nesterboy [21]

Answer:

Step-by-step explanation:

x and 2x are linear pair angles.

Sum of linear pair angles is 180,

x + 2x = 180

3x = 180

x = 180 / 3

x = 60

Therefore,

the value of x is 60.

6 0

3 years ago

Read 2 more answers

Area of the bounded curves y=x^2, y=√(7+x)

N76 [4]

Answer:

$\displaystyle \int\limits^{1.718}_{-1.529} {\sqrt{7 + x} - x^2} \, dx = 5.74773$

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Addition/Subtraction]: $\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Integration

Integrals

Integration Rule [Reverse Power Rule]: $\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C$

Integration Rule [Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)$

Integration Property [Addition/Subtraction]: $\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx$

U-Substitution

Area of a Region Formula: $\displaystyle A = \int\limits^b_a {[f(x) - g(x)]} \, dx$

Step-by-step explanation:

Step 1: Define

$\displaystyle \left \{ {{y = x^2} \atop {y = \sqrt{7 + x}}} \right.$

Step 2: Identify

Graph the systems of equations - see attachment.

Top Function: $\displaystyle y = \sqrt{7 + x}$

Bottom Function: $\displaystyle y = x^2$

Bounds of Integration: [-1.529, 1.718]

Step 3: Integrate Pt. 1

Substitute in variables [Area of a Region Formula]: $\displaystyle \int\limits^{1.718}_{-1.529} {\sqrt{7 + x} - x^2} \, dx$
[Integral] Rewrite [Integration Property - Addition/Subtraction]: $\displaystyle \int\limits^{1.718}_{-1.529} {\sqrt{7 + x} - x^2} \, dx= \int\limits^{1.718}_{-1.529} {\sqrt{7 + x}} \, dx - \int\limits^{1.718}_{-1.529} {x^2} \, dx$
[Right Integral] Integration Rule [Reverse Power Rule]: $\displaystyle \int\limits^{1.718}_{-1.529} {\sqrt{7 + x} - x^2} \, dx= \int\limits^{1.718}_{-1.529} {\sqrt{7 + x}} \, dx - \frac{x^3}{3} \bigg| \limits^{1.718}_{-1.529}$
Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^{1.718}_{-1.529} {\sqrt{7 + x} - x^2} \, dx= \int\limits^{1.718}_{-1.529} {\sqrt{7 + x}} \, dx - 2.88176$

Step 4: Integrate Pt. 2

Identify variables for u-substitution.

Set u: $\displaystyle u = 7 + x$
[u] Basic Power Rule [Derivative Rule - Addition/Subtraction]: $\displaystyle du = dx$
[Limits] Switch: $\displaystyle \left \{ {{x = 1.718 ,\ u = 7 + 1.718 = 8.718} \atop {x = -1.529 ,\ u = 7 - 1.529 = 5.471}} \right.$

Step 5: Integrate Pt. 3

[Integral] U-Substitution: $\displaystyle \int\limits^{1.718}_{-1.529} {\sqrt{7 + x} - x^2} \, dx= \int\limits^{8.718}_{5.471} {\sqrt{u}} \, du - 2.88176$
[Integral] Integration Rule [Reverse Power Rule]: $\displaystyle \int\limits^{1.718}_{-1.529} {\sqrt{7 + x} - x^2} \, dx = \frac{2x^\Big{\frac{3}{2}}}{3} \bigg| \limits^{8.718}_{5.471} - 2.88176$
Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^{1.718}_{-1.529} {\sqrt{7 + x} - x^2} \, dx = 8.62949 - 2.88176$
Simplify: $\displaystyle \int\limits^{1.718}_{-1.529} {\sqrt{7 + x} - x^2} \, dx = 5.74773$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

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3 years ago

For x > 3, values of the function f(x) = –(x – 3)^2(x + 2) are negative. On this same interval, which statement correctly des

Leokris [45]

The addictive inverse is positive while the multiplicative inverse is negative

4 0

4 years ago

Read 2 more answers

I am not able to solve this problem

Soloha48 [4]

First, 0.0004853 is < 1, so we need to multiply the number by 10 to a negative power if it's greater than 1 (if that makes sense i cant describe it better)

So, b and c is incorrect.

10 to the power of negative 4 = 0.0001, and 4.853 x 0.0001 = 0.0004853 (true), so answer is a

8 0

2 years ago

Read 2 more answers

nikki grows 12 tomato plants. she measures their heights to the nearest centimetre, and writes them down. Complete the frequency

sdas [7]

Answer:

Nikki grows 20 tomato plants and she measures their heights.

We want to complete the frequency table.

All we have to do is count the number of values that fall between each range.

The values are:

5 10 12 16 14

17 20 15 10 7

13 11 6 18 15

6 12 17 8 12

Height Frequency

-> 5 ≤ h < 10 5

10 ≤ h < 15 8

15 ≤ h < 20 6

20 ≤ h < 25 1

5 0

4 years ago

Plese help im in 2nd grade and this is really hard all the kids in my class know it but me​

Plese help im in 2nd grade and this is really hard all the kids in my class know it but me