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Komok [63]
2 years ago
5

H. E. L. P. ???!!!!!!​

Mathematics
1 answer:
vladimir1956 [14]2 years ago
4 0

Answer:

C

Step-by-step explanation:

sin x= CB/CA =4/8

......

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I have a thanksgiving packet. I’m stuck on these last two pages. Can anyone help me on the question. Thanks.
vovikov84 [41]
I think the Honda and Dodge have the same ratio. If you do the math, the ratio will come out to (12,1) or 12 for both types of cars.
6 0
3 years ago
3q + 3j <br>if q= 7 and j = 4​
Flura [38]

Answer:

33

Step-by-step explanation:

3q + 3j

if q= 7 and j = 4​

3(7) + 3(4) = 21 + 12 = 33

7 0
2 years ago
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The student council raised $150 during the school dance if they charge $3per ticket and received $24 in other donations what is
IRINA_888 [86]
3t + 24 = 150 this is the answer
3 0
3 years ago
What is the scale factor
nadezda [96]

Answer:

2/5

Step-by-step explanation:

Since it's from a big square to a smaller square, the smaller number will be at the top. Also, use the same side to find the scale factor, but since this is a square and all sides of a square are equal, it doesn't matter but in other shapes it does so practice i guess:

Left side of big square: 5

Left side of small square: 2

So scale is 2/5

To confirm:

5 · 2/5 = 10/5 = 2, we're right

5 0
3 years ago
Read 2 more answers
Help me please Only no.2 no.3 no.8 no.6 no.9 and no.10
Reil [10]

Answer:

2) x³ (x² + 1) (x + 1)

3) (x - 6) (x + 6)

6)  (x + 3) (x - 4)

8) (5x + 3) (x - 2)

Step-by-step explanation:

I'm providing the solutions for numbers 2, 3, 6, and 8, in order to give you the opportunity to apply and practice the techniques demonstrated here for numbers 9 and 10.

<h3>2) x⁶ + x⁵ + x⁴ + x³ = 0 </h3>

Factor out the highest possible common term, applying the product rule of exponents, a^{m} a^{n} = a^{m+n}

x³ (x³ + x² + x¹ + 1) = 0

Next, apply the special factoring technique into the exponential expressions inside the parenthesis), the factor by grouping:

The factors for the given polynomial are: x³ (x² + 1) (x + 1)

<h3> 3) x² - 36 = 0 </h3>

Use the <u>difference of two squares factoring</u>, where it states: u² - v² = (u - v) (u + v)

Since 36 is a perfect square of 6², then we can establish the following factors using the difference of squares:

Factors:  (x - 6) (x + 6).

<h3>6) x² - x - 12 = 0 </h3>

For this quadratic trinomial, find factors that will produce a product of <em>a</em> × <em>c</em> (1 × -12) and sum of b (-1):

The possible factors of -12 that also results to a sum of -1 are:  

3 × -4 = -1

 Hence, the possible factors of x² - x - 12 = 0 could be (x + 3) (x - 4). Verify whether this is correct by performing the FOIL method:

(x + 3) (x - 4) = x² - 4x + 3x - 12 = x² - x - 12

Therefore, the factors of x² - x - 12 = 0 are: (x + 3) (x - 4).

<h3>8) 5x² - 7x - 6 = 0 </h3>

where a = 5, b = -7, and c = -6

Given this quadratic trinomial, we can use the factoring by grouping, where it states: find the values of u and v such that the product of uv is the same as the product of <em>ac</em>:  u × v = a × c, and that the sum of (<em>u</em> + <em>v </em>) is the same as <em>b</em>.  

In other words, we must find the factors of u × v that have a product of a × c and a sum of b:

<em>u × v </em>= <em>a × c</em> = 5 × (-6) = -30  

u + v = b = -7

The possible factors of -30 are:

-3 × 10 = -30

3 × -10 = -30

Out of these factors, the factors 3 × -10 = -30 will have the same sum as the value of b = -7:

3 + (-10) = -7

Hence, u = 3, v = -10.

Now, we can group the trinomial as follows:

(<em>ax</em>² + <em>ux </em>) + (<em>vx </em>+ <em>c </em>)

(5x² + 3x) + (-10x - 6)

For the last step, factor out the common terms from both groups:

(5x² + 3x) + (-10x - 6)  

x (5x + 3) - 2(5x + 3)

Combine common terms together: (5x + 3) and (x - 2)

Therefore, the factors of the given quadratic trinomial are: (5x + 3) (x - 2).

5 0
2 years ago
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