Answer: 0.0174
Step-by-step explanation:
Given : 
Let x be the random variable that represents the weight of the drumsticks.
We assume that the weight of the drumsticks is normally distributed.
Now, the z-score for x=2.23 ,
Using z-value table , we have
P-value =P(x≥2.23)=P(z≥2.11)=1-P(z<2.11)=1-0.9825708
=0.0174292≈0.0174 [Rounded nearest 4 decimal places]
Hence, the probability of the stick's weight being 2.23 oz or greater = 0.0174
Answer:
i do not know
Step-by-step explanation:
well first off u didn't give the graph at all which makes it impossible to answer.
Answer:
6
Step-by-step explanation:
Answer:
The first expression can be rewritten as
35 {b}^{2} = 5 \times 7 \times {b}^{2}35b
2
=5×7×b
2
The second expression is rewritten as
15 {b}^{3} = 3 \times 5 {b}^{3}15b
3
=3×5b
3
The third expression is
5b = 5 \times b5b=5×b
The greatest common factor is the product of the least powers of the common factors.
