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Makovka662 [10]
2 years ago
12

Grace's work is x miles from her house. She drives to work every day of a 5-day workweek. Grace also goes to the gym every day a

fter work, which increases her daily drive by 8 miles. The following expression shows the number of miles Grace puts on her car during the workweek. Which of the following descriptions are equivalent ways to write this problem? Grace's work is x miles from her house. To get to work and back, she drives x miles. She does this 5 times during the workweek. She also goes to the gym to work out which increases her daily driving by 8 miles. She does this 5 times. Grace's work is x miles from her house. During the workweek, she drives the x miles between her house and work 7 times. She also goes to the gym to work out which increases her driving by 13 miles per workweek. Grace's work is x miles from her house. To get to work and back, she drives 2x miles. She does this 5 times during the workweek. She also goes to the gym to work out which increases her daily driving by 8 miles. She does this 5 times. Grace's work is x miles from her house. During the workweek, she drives the x miles between her house and work 10 times. She also works out which increases her driving by 40 miles per workweek.
Mathematics
1 answer:
e-lub [12.9K]2 years ago
3 0

Answer:

El dirves unos 60 Km durante todo el recorrido unas 5 vweces a las semana

Step-by-step explanation:

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80

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For the following linear system, put the augmented coefficient matrix into reduced row-echelon form.
Anni [7]

Answer:

The reduced row-echelon form of the linear system is \left[\begin{array}{cccc}1&0&-5&0\\0&1&3&0\\0&0&0&1\end{array}\right]

Step-by-step explanation:

We will solve the original system of linear equations by performing a sequence of the following elementary row operations on the augmented matrix:

  1. Interchange two rows
  2. Multiply one row by a nonzero number
  3. Add a multiple of one row to a different row

To find the reduced row-echelon form of this augmented matrix

\left[\begin{array}{cccc}2&3&-1&14\\1&2&1&4\\5&9&2&7\end{array}\right]

You need to follow these steps:

  • Divide row 1 by 2 \left(R_1=\frac{R_1}{2}\right)

\left[\begin{array}{cccc}1&3/2&-1/2&7\\1&2&1&4\\5&9&2&7\end{array}\right]

  • Subtract row 1 from row 2 \left(R_2=R_2-R_1\right)

\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\5&9&2&7\end{array}\right]

  • Subtract row 1 multiplied by 5 from row 3 \left(R_3=R_3-\left(5\right)R_1\right)

\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\0&3/9&9/2&-28\end{array}\right]

  • Subtract row 2 multiplied by 3 from row 1 \left(R_1=R_1-\left(3\right)R_2\right)

\left[\begin{array}{cccc}1&0&-5&16\\0&1/2&3/2&-3\\0&3/9&9/2&-28\end{array}\right]

  • Subtract row 2 multiplied by 3 from row 3 \left(R_3=R_3-\left(3\right)R_2\right)

\left[\begin{array}{cccc}1&0&-5&16\\0&1/2&3/2&-3\\0&0&0&-19\end{array}\right]

  • Multiply row 2 by 2 \left(R_2=\left(2\right)R_2\right)

\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&-19\end{array}\right]

  • Divide row 3 by −19 \left(R_3=\frac{R_3}{-19}\right)

\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&1\end{array}\right]

  • Subtract row 3 multiplied by 16 from row 1 \left(R_1=R_1-\left(16\right)R_3\right)

\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&-6\\0&0&0&1\end{array}\right]

  • Add row 3 multiplied by 6 to row 2 \left(R_2=R_2+\left(6\right)R_3\right)

\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&0\\0&0&0&1\end{array}\right]

8 0
3 years ago
3.8x = −104.12 what is the answer to the question
Elina [12.6K]

Answer:

-27.4

Step-by-step explanation:

7 0
3 years ago
Order the numbers from least to greatest.<br> 23% , 1/4 , 0.225 .
Alla [95]
0.225, 23%, 1/4


Step my step

23% = 0.23
1/4 = 0.25
3 0
2 years ago
What is 456,420 divided by 8.75 million
Travka [436]
<span>
0.05216228571 is the answer.</span>
3 0
3 years ago
The ratio between the radius of the base and the height of the cylinder is 2:3.if its volume is 1617cm^3,the total surface area
zalisa [80]
The answer is 769.3 cm²

The volume of the cylinder is : V = π r² h
<span>The ratio between the radius of the base and the height of the cylinder is 2:3:
r/h = 2/3
h = 3/2r

V = 1617 cm
</span>π = 3.14

1617 = πr² * 3/2 r
1617 = πr³ * 3/2
1617 * 2/3 = πr³
1078 = πr³
r³ = 1078/π = 1078/3.14 = 343
r = ∛343 = 7 cm

h = 3/2r = 3/2 * 7 = 10.5 cm


The surface area of the cylinder is:
SA = 2πr² + 2πrh
      = 2 * 3.14 * 7² + 2 * 3.14 * 7 * 10.5
      = 307.72 + 461.58
      = 769.3 cm²
5 0
3 years ago
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