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Evgen [1.6K]
3 years ago
5

Explain how to write an equation of a line given the slope and one point on the line

Mathematics
2 answers:
Mamont248 [21]3 years ago
5 0
Equation of the line is slope intercept form correct? Ok, slope intercept is y=MX+b. M is slope, x is the point, and b is the y intercept. If you are trying to find b then plug your x and y values plus your slope and once you have b put that in the equation. After that you could take out the x and y values to put the variables x and y and that's you equation of a line
Roman55 [17]3 years ago
4 0
It’s written in y=mx+b I think
The slope is M
B is where it hits on the y-intercept
Hopefully this helps

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A 9-kilogram bag of sugar cost $27.54. what is the unit price ?
shusha [124]

Answer:

$3.06

Step-by-step explanation:

1 kg = $27.54

27.54/9 kilogram

4 0
3 years ago
15. Suppose a box of 30 light bulbs contains 4 defective ones. If 5 bulbs are to be removed out of the box.
Naddika [18.5K]

Answer:

1) Probability that all five are good = 0.46

2) P(at most 2 defective) = 0.99

3) Pr(at least 1 defective) = 0.54

Step-by-step explanation:

The total number of bulbs = 30

Number of defective bulbs = 4

Number of good bulbs = 30 - 4 = 26

Number of ways of selecting 5 bulbs from 30 bulbs = 30C5 = \frac{30 !}{(30-5)!5!} \\

30C5 = 142506 ways

Number of ways of selecting 5 good bulbs  from 26 bulbs = 26C5 = \frac{26 !}{(26-5)!5!} \\

26C5 = 65780 ways

Probability that all five are good = 65780/142506

Probability that all five are good = 0.46

2) probability that at most two bulbs are defective = Pr(no defective) + Pr(1 defective) + Pr(2 defective)

Pr(no defective) has been calculated above = 0.46

Pr(1 defective) = \frac{26C4  * 4C1}{30C5}

Pr(1 defective) = (14950*4)/142506

Pr(1 defective) =0.42

Pr(2 defective) =  \frac{26C3  * 4C2}{30C5}

Pr(2 defective) = (2600 *6)/142506

Pr(2 defective) = 0.11

P(at most 2 defective) = 0.46 + 0.42 + 0.11

P(at most 2 defective) = 0.99

3) Probability that at least one bulb is defective = Pr(1 defective) +  Pr(2 defective) +  Pr(3 defective) +  Pr(4 defective)

Pr(1 defective) =0.42

Pr(2 defective) = 0.11

Pr(3 defective) =  \frac{26C2  * 4C3}{30C5}

Pr(3 defective) = 0.009

Pr(4 defective) =  \frac{26C1  * 4C4}{30C5}

Pr(4 defective) = 0.00018

Pr(at least 1 defective) = 0.42 + 0.11 + 0.009 + 0.00018

Pr(at least 1 defective) = 0.54

3 0
3 years ago
Does this graph show a constant or variable rate of change?
valentinak56 [21]

Answer:

constant

Step-by-step explanation:

5 0
3 years ago
wanting some extra help with factoring while knowing what method it would be like gcf or grouping etc
Ksju [112]

d) You have a <u>difference of squares</u>:

49y² - 9 = (7y)² - 3²

Recall the identity,

a² - b² = (a - b) (a + b)

So,

49y² - 9 = (7y - 3) (7y + 3)

e) Pull out the common factor 3 from each term:

3x² - 3x - 90 = 3 (x² - x - 30)

Now use the <u>sum-product method</u>. Notice that we can write 30 = 5 • 6, and 5 - 6 = 1, so

3x² - 3x - 90 = 3 (x + 5) (x - 6)

f) Same as in (e), use the <u>sum-product method</u>. Notice that 42 = 7 • 6, and -7 - 6 = -13, so

x² - 13x + 42 = (x - 7) (x - 6)

8 0
2 years ago
Read 2 more answers
Can someone help me
Daniel [21]
Y=10x+8
8 is the y intercept because it’s when x=0
3 0
3 years ago
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